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dmitriy555 [2]
3 years ago
14

For the function G defined by G(x)=5x+3, find G(r+5).

Mathematics
2 answers:
ycow [4]3 years ago
4 0

Answer:

8x+5

Step-by-step explanation:

any letter will mean 1

trasher [3.6K]3 years ago
3 0

Answer:

5(r+5)+3=5r+25+3=5)]

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Find the circumference of a circle with a radius of 2 inches. Give an exact answer.
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Step-by-step explanation:

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Complete the factored form.<br>3x4 + 16x + 21 = (3x + 7)( )​
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Answer:

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Step-by-step explanation:

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Read 2 more answers
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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