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3 years ago

13

How do you find the Y intercept ? I’m having some trouble

2 answers:

NISA [10]3 years ago

7 0

Answer:

so on a graph you have two axis's: the x (horizontal) and y (vertical). The y intercept is the point at which your line touches the y axis which is also when x=0. So your y intercept will always be (0,y) in this case when x is t and when t is 0, C (or y) is 8. x is your input (independent) and y is your output (dependent). The y intercept in the above model can be written as (0,8) or m=8

Step-by-step explanation:

marishachu [46]3 years ago

4 0

Answer:

The y intercept is always (0,y) so in this case it is (0,8)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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scoundrel [369]

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Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

Pepsi [2]

Answer:

Option 3 - $y=-6x+28$

Step-by-step explanation:

Given : Perpendicular to the line $x - 6y = 8$ ; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation $x - 6y = 8$

Converting into slope form $y=mx+c$ ,

Where m is the slope.

$y=\frac{x-8}{6}$

$y=\frac{x}{6}-\frac{8}{6}$

The slope of the equation is $m=\frac{1}{6}$

The slope of the perpendicular equation is $m_1=-\frac{1}{m}$

The required slope is $m_1=-\frac{1}{\frac{1}{6}}$

$m_1=-6$

The required equation is $y=-6x+c$

Substitute point (x,y)=(4,4)

$4=-6(4)+c$

$4=-24+c$

$c=28$

Substitute back in equation,

$y=-6x+28$

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xxTIMURxx [149]

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