Simran's Journey was 35 minutes less on Thursday as compared to Wednesday
<h3>What is a Distance - Time Graph ?</h3>
Distance Time graph is the relationship between the distance travelled in the respective time on the x axis.
Two distance time graph is given
The Wednesday graph shows the time taken by Simran is
Total Time = 40 minutes
and
The Thursday graph shows the time taken by Simran is
Total Time = 5 minutes
Therefore Simran's Journey was 40-5 , 35 minutes less on Thursday as compared to Wednesday
To know more about Distance - Time Graph
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Answer:
The relation on the bottom left, where the mouse is, is the function. Hope this helps :)
Answer:
No
Step-by-step explanation:
Multiplying the 2 and the 5 by 3 will get you 6 and 14. 14 is not a factor of 5 making it incorrect.
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Answer:
148
Step-by-step explanation:
a line (cd) is 180°
cba + and must be 180°
180-33=148