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3 years ago

HEELLPPPPPpppppppppppppppp

Physics

1 answer:

GuDViN [60]3 years ago

6 0

Explanation:

Given:

$A_1$ = 4.5 cm $^2$

$v_1$ = 40 cm/s

$v_2$ = 90 cm/s

$A_2$ = ?

a) The continuity equation is given by

$A_1v_1 = A_2v_2$

Solving for $A_2$ ,

$A_2 = \dfrac{v_1}{v_2}A1 = \left(\dfrac{40\:\text{cm/s}}{90\:\text{cm/s}}\right)(4.5\:\text{cm}^2)$

$= 2\:\text{cm}^2$

b) If the cross-sectional area is reduced by 50%, its new area $A_2'$ now is only 1 cm^2, which gives us a radius of

$r = \sqrt{\dfrac{A_2'}{\pi}} = 0.564\:\text{cm}$

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Read 2 more answers

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The answer to the question is

The current through R4 = 0.5865 mA

Explanation:

To solve this we list out the known thus

Voltage source = 45-V

Firsrt parallel circiuit has resistances of R1 = 17 kΩ and R2 = 23 kΩ

Second parallel circiuit has resistances of R3 = 45 kΩ and R4 = 55 kΩ

we first find the current flowing in the circuit by finding thr sum of the total resistance in eah parallel circuit

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Similarly we have for the second parallel circuit 1/RT2 = 1/R3 + 1/R4

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This means that the 9.775 kΩ and the 24.75 kΩ are in series hence total resistance of the circuit = sum of all resistances in series

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