Answer:
E = 4.75 x 10⁻¹⁶ J
Explanation:
given,
wavelength of the x-ray , λ = 4.18 Å
Energy of photon = ?
we know
where h is the planks constant
c is the speed of light
h = 6.626 x 10⁻³⁴ m² kg / s
c = 3 x 10⁸ m/s
now,
E = 4.75 x 10⁻¹⁶ J
hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J
Answer:
The charge passes a given point in the conductor during this time is 9.8 C.
Explanation:
Given that,
Current = 1.4 A
Time = 7.0 sec
We need to calculate the charge during this time
Charge :
Charge is the product of current and time.
In mathematically form,
Where, i = cirrent
t = time
Put the value into the formula
Hence, The charge passes a given point in the conductor during this time is 9.8 C.
Answer:
b. 12.5 mAs, 70 kVp
Explanation:
The given parameter are;
The initial exposure factors := 10 mAs and 70 kVp
The initial Grid Ratio, G.R.₁ = 8:1
The Grid Ratio with which the radiographer desires to increase the scatter absorption, G.R.₂ = 12:1
Given that the lead content in the 12:1 grid, is higher than the lead content in 8:1 grid and that 12:1 grid needs more mAs to compensate, and provides a higher image contrast, the amount of extra mAs is given by the Grid Conversion Factors, GCF, as follows;
The GCF for G.R. 8:1 = 4
The GCF for G.R. 12:1 = 5
Therefore, given that the mAs used by the radiographer for 8:1 Grid Ratio is 10 mAs, the mAs required for a G.R. of 12:1 in order to maintain the same exposure is given as follows;
mAs for G.R. of 12:1 = 10 mAs × 5/4 = 12.5 mAs
Therefore the new exposure factors are;
12.5 mAs, 70 kVp
The power output is 6500 J - ( 12% of 6500 J)
= 5460 J .
Is the first question complete? Because the work done by the river would be equal to work done by the axle of the wheel.
