A bodybuilder loads a bar with 550 Newtons (~125 pounds) of weight and pushes the bar over her head 10 times. Each time she lift
2 answers:
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Answer:
Voltage of the secondary coil is 720 volts.
Explanation:
Number of turns in primary coil, N₁ = 60
Number of turns in secondary coil, N₂ = 360
Input rms voltage of primary coil, V₁ = 120 V
We have to find the output rms voltage of the secondary coil. The relationship between the number of coil and voltage is given by :
V₂ = output rms voltage of the secondary coil.
After solving above equation, we get :
V₂ = 720 V
Hence, the output rms voltage of the secondary coil is 720 volts.
The magnitude of the magnetic force per unit length on the top wire is
2×10⁻⁵ N/m
<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula
F=
Here we are given,
= magnetic permeability
= 4×10⁻⁷ H m⁻¹
If= 12 A
d= distance from each wire to point.
=0.12m
Now we put the known values in the above equation, we get
F=
Or, F =
Or, F= 2×10⁻⁵ N/m.
From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.
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