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blagie [28]
3 years ago
11

A bodybuilder loads a bar with 550 Newtons (~125 pounds) of weight and pushes the bar over her head 10 times. Each time she lift

s the weight 0.5 meters. How much work did she do?
Physics
2 answers:
tangare [24]3 years ago
5 0
<span>  (550 N) X (0.5 m) = 275 joules</span>
mafiozo [28]3 years ago
3 0

Work = (force) x (distance)

Each time she lifts the weight, she does

          (550 N) x (0.5 m) = 275 joules of work against gravity.

Each time she lets the bar down gently, gravity does

          (550 N) x (0.5 m) = 275 joules of work against her muscles. 

If the human physical muscular system were 100% efficient, and capable
of absorbing work as well as spending it, then the bodybuilder would do
exactly zero work in the process of 1-up followed by 1-down.


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Consider two diffraction gratings with the same slit separation. The only difference between the two gratings is that one gratin
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Answer:

True The grid with more slits gives more angle separation increases

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Explanation:

Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is

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For network with 5 slits

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For the network with 10 slits

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let's calculate the separation (teat) for each one

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for 5 slits

     θ₅ = sin⁻¹ (m λ 5)

for 10 slits

     θ₁₀ = sin⁻¹ (m λ 10)

we can appreciate that for more slits the angle increases

the intensity of a series of slits is

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let's analyze the claims

False

True The grid with more slits gives more angle separation increases

False

True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases

False

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5 0
3 years ago
Read 2 more answers
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