Answer:
The speed of the car at the apex of the loop must be grater than 2.45 m/s
Explanation:
In order for the car to not fall off the track at the apex of the loop, the norm force of the track at the apex must be greater than zero.
Assuming frictionless life on the track which is also to have a perfectly circular shape near the top (radius being 0.25m), the norm force of the track and gravity both point down and result in the centripetal force:
The formula for centripetal force on a circular trajectory is
and so the condition for the car to stay on the track can be written as
The speed of the car at the apex of the loop must be grater than 2.45 m/s
Answer:
Explanation:
A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km
Check attachment for diagram
The intensity of the position vector is equal to the displacement,
So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.
So, applying Pythagorean theorem
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
Verifique el adjunto para ver el diagrama
La intensidad del vector de posición es igual al desplazamiento,
Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.
Entonces, aplicando el teorema de Pitágoras
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
Answer:
C) Newton's law of inertia
Explanation:
The law states that a body will continue in its state of rest or uniform motion unless compel by some external forces (acted upon by an unbalanced force) to act otherwise. In this case the golf will remain in it state because the downward force of gravity is equal to the upward force of normal and the horizontal vector sum of the forces acting on the body is zero.
Answer: 
Explanation:
Given
Water column height 
After oil is poured, the total height becomes 
Pressure at the bottom will be the sum due to the water and oil column
Suppose the density of the oil is 
Pressure at the bottom
![\Rightarrow P=10^3\times g\times 25+900\times g\times 15\\\Rightarrow P=100g[250+135]\\\Rightarrow P=3773\times 100\ Pa\\\Rightarrow P=377.3\ kPa](https://tex.z-dn.net/?f=%5CRightarrow%20P%3D10%5E3%5Ctimes%20g%5Ctimes%2025%2B900%5Ctimes%20g%5Ctimes%2015%5C%5C%5CRightarrow%20P%3D100g%5B250%2B135%5D%5C%5C%5CRightarrow%20P%3D3773%5Ctimes%20100%5C%20Pa%5C%5C%5CRightarrow%20P%3D377.3%5C%20kPa)
