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2 years ago

PLEASE I NEED THIS DONE BY MIDNIGHT HELP

Mathematics

1 answer:

Readme [11.4K]2 years ago

5 0

Answer:

Khalid’s rate is ___140_ miles per hour. Jesse’s rate is _150___ miles per hour. So, _Jesse’s___ train traveled at a faster speed.

Step-by-step explanation:

The general equation of a straight line is

y = mx + b

for y = 150x

We have the slope as 150

This is 150 miles/hour

This relates to Jesse’s train speed

for Khalid, we have his own speed obtainable from the graph

The speed is simply the slope of the graph

We proceed to select two points from the graph and find the slope

The points are; ((1,140) and (4,560)

Mathematically, the slope will be;

m = (y2-y1)/(x2-x1)

m = (560-140)/(4-1) = 420/3 = 140 miles per hour

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What’s the answer I really need help????

Brums [2.3K]

You should use the calculator and just plug in those numbers

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3 years ago

Read 2 more answers

Wai Kit had $45 more than Cheryl and 0.25 of what Zheng Yi had. If they had $510 altogether, how much less money did Cheryl have

GenaCL600 [577]

Step-by-step explanation:

Wai 1unit+45

Cheryl 1unit

Zheng 4units+180

Altogether 6units+225=510

6units = 510-225

6units=285

1unit=285÷6

= $47.5

So Wai =47.5+45 = 92.5

Cheryl =47.5

Zheng =4×47.5+180 =370

370-47.5=$322.5

Answer $322.5

4 0

2 years ago

A restaurant operator in Accra has found out that during the lockdown,if she sells a plate of her food for Ghc 20 each,she can s

ella [17]

The demand equation illustrates the price of an item and how it relates to the demand of the item.

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85

From the question, we have:

$Plates = 300$

$Price = 20$

The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:

$\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}$

The slope (m) is calculated using:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{25-20}{290-300}$

$m = \frac{5}{-10}$

$m = -\frac{1}{2}$

The equation of the demand is as follows:

The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).

Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).

So, the demand equation is:

$R(x) = (300 - 10x) \times (20 + 5x)$

Open the brackets to calculate the maximum revenue

$R(x) =6000 + 1500x - 200x - 50x^2$

$R(x) =6000 + 1300x - 50x^2$

Equate to 0

$6000 + 1300x - 50x^2 =0$

Differentiate with respect to x

$1300 - 100x =0$

Collect like terms

$100x =1300$

Divide by 100

$x =13$

So, the price at maximum revenue is:

$Price= 20 + 5x$

$Price= 20 + 5 * 13$

$Price= 85$

In conclusion:

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85