What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then
y + 1 = 0
y = -1
so x - y = 6
x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".
Answer:
x = 8
Step-by-step explanation:
Since < A and < B are vertical angles, then it means that they have the same measure.
Given that m < A = (3x - 21)°, and m < B = (2x - 13)°:
We can set up the following equation to solve for the value of x:
m < A = m < B
(3x - 21)° = (2x - 13)°
3x - 21 = 2x - 13
Subtract 2x from both sides:
3x - 2x - 21 = 2x - 2x - 13
x - 21 = -13
Add 21 to both sides to isolate and solve for the value of x:
x - 21 + 21 = -13 + 21
x = 8
We must verify if we have the correct value for x by plugging in 8 into the equality statement:
(3x - 21)° = (2x - 13)°
[3(8) - 21]° = [2(8) - 13]°
(24 - 21)° = (16 - 13)°
3° = 3° (True statement. This means that we have the correct value for x).
Therefore, the value of x = 8.
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Answer:
Equation of line 1 is 3 X - 4 Y = 20
Equation of line 2 is 3 X + 4 Y = 20
Step-by-step explanation:
Given co ordinates of points as,
( -4 , 8) and (0 , 5)
From the given two points we can determine the slop of a line
I. e slop (m) = 
Or, m = 
So, m = 
Now equations of line can be written as ,
Y - y1 = m ( X - x1)
<u>At points ( -4 , 8)</u>
Y - 8 = (X + 4)
So , Equation of line 1 is 3 X - 4 Y = 20
<u>Again with points ( 0 , 5)</u>
Y - 5 = ( X - 0)
So, Equation of line 2 is 3 X + 4 Y = 20
Hence Equation of line 1 is 3 X - 4 Y = 20 and Equation of line 2 is 3 X + 4 Y = 20 Answer
No it isn't the solution to this equation is 2/1
