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3 years ago

A doctor can complete 3 examinations in 2 hours. How many examinations can the doctor complete in 5 hours?

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

7 0

I think it should be 7 since 3x2=6 and and 6+1.5 Is 7.5 but he cant help one half of a patient

Levart [38]3 years ago

3 0

I believe it to be six but than again I could be sadly wrong

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Help plssssssssssssssssssss

Whitepunk [10]

Answer: -74

Step-by-step explanation:

First you have to solve - 2y - 9 = 7 to find what "y" equals so we can plug that into 9y - 2

1. Solve -2y - 9 =7:

-2y = 16

y = -8

2. Plug -8 into the expression 9y - 2:

9(-8) - 2

-72 -2

-74!

Im sorry if i didnt do this correctly :/

5 0

3 years ago

Identify the terms of the expression. 3r^2+4r+8

Andreas93 [3]

Answer:

The terms

Step-by-step explanation:

The terms in this expression are coefficients, constants, variables, and exponents. 3 and 4 would be the coefficients. 8 would be the constant. r is the variable and 2 is the exponent.

4 0

2 years ago

Read 2 more answers

Please help! I attached the question below.

kompoz [17]

Answer:

$\frac{2(c+2)}{c(c-2)}$

Step-by-step explanation:

$\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }$

Identity used:

$a^{2}-b^{2}=(a-b)(a+b)$

$\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }$

Now let us divide the modified expressions:

$\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})}$ ÷ $\frac{(c-2)^2}{2(6c^{3}+15c^{2}) }$

we get:

$\frac{2(c+2)}{c(c-2)}$

5 0

3 years ago

Help me please thanks.

kap26 [50]

Answer:

Step-by-step explanation:

4 0

2 years ago

The sum of 5 consecutive odd numbers is 135 what is the second number in this sequence

hoa [83]

Step-by-step explanation:

x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 135

5·x + 20 = 135

5·x = 115

x = 23

So the sequence is

23, 25, 27, 29, 31

The second number is 25.

Do you agree?

6 0

3 years ago