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2 years ago

Substances can be categorised in two ways: as an element, mixture or compound ora as a solid, liquid or gas. which

Chemistry

2 answers:

Ray Of Light [21]2 years ago

8 0

Answer:

hi im sorry wehere are from

adoni [48]2 years ago

6 0

Answer:

Most substances on earth are compounds and most interesting chemistry is done with compounds. Most interesting chemistry is done with mixtures of compounds although they often start with pure compounds and then do reactions as mixtures. Most chemistry is carried out in liquid solutions made up of compounds that are solids, liquids, or gases in their pure form.

Explanation:

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Paul added a sample of bromic acid to water and found the pOH to be 10. What is the pH of the solution?

Ket [755]

Answer:

Explanation:

pH + pOH = 14

pH + 10 = 14

pH = 14 - 10 = 4

Therefore pH of the solution is 4 .

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2 years ago

vanillin is a flavoring agent in vanilla it has a mass percent composition of 61.15% c,5.3%H,31.55% o determine the empirical fo

Nutka1998 [239]

The empirical and molecular formulas will be $C_5H_5O_2$ and $C_1_0H_1_0O_4$ respectively.

<h3>Empirical and molecular formula</h3>

The compound contains C, H, and O.

C = 61.15/12 = 5.0958

H = 5.3/1 = 5.3

O = 31.55/16 = 1.9719

Divide by the smallest

C = 2.6

H = 2.7

O = 1

Thus, the empirical formula is $C_5H_5O_2$

Empirical formula mass = (12x5) + (1x5) + 16x2 = 97

n = 152.15/97 = 2

The molecular formula is $C_1_0H_1_0O_4$

More on molecular and empirical formulas can be found here: brainly.com/question/14425592

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1 year ago

I need help with unit conversion

saw5 [17]

Answer:

what is it?

Explanation:

you haven't said?

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2 years ago

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Alex17521 [72]

<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 91.2321 \ g \ Mn$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0

2 years ago

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