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alisha [4.7K]
2 years ago
10

Identify the charge on the atom or ion that has one proton, zero neutrons, and zero electrons.

Chemistry
1 answer:
MAVERICK [17]2 years ago
3 0

Answer:

The emission spectrum of gold shows a line of wavelength 2.676 x 10-7 m. How much energy is emitted as the excited electron falls to the lower energy level?

(a) 7.43 x 10-19 J

(b) 5.30 x 10-20 J

(c) 6.05 x 10-19 J

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Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?
IRINA_888 [86]
Density (p) is defined as the mass (m) per unit volume (v) or:

p = m/v 

Using this relationship, the volume is:

v = m/p

Using the given values of mass of 80 grams and density of 8 g/cm3, the sample volume is:

v = 80 grams/8 grams/cm3
v = 10 cm3

The final answer is 10 cm3.
7 0
4 years ago
An object has a mass of 33g and a volume of 11ml. What is it's density?
astra-53 [7]

Answer:

3g/ml

Explanation:

Density = \frac{33g}{11ml}

33 divided by 11 = 3

5 0
4 years ago
10. What base unit of measurement is common to all systems?
Lera25 [3.4K]

Answer:

The SI system , also called theatrics system, is used around the world

5 0
3 years ago
A nuclide of phosphorus 3015P decays into a nuclide of silicon 3014Si. In order to satisfy charge conservation and lepton number
jeka94

In order to satisfy charge conservation and lepton number conservation the other products must be neutron.

<h3>What is conservation of mass?</h3>

The principle of conservation of mass states that, the sum of the initial mass of reactants must be equal to final mass of the products.

_{15}^{30}P\ --- > \ _{14}^{30} Si \ + \ ^{0}_{1} n

The balanced reaction of radioactive decay of phosphorous shows conservation of mass.

Thus, in order to satisfy charge conservation and lepton number conservation the other products must be neutron.

Learn more about radioactive decay here: brainly.com/question/1383030

#SPJ1

3 0
2 years ago
The reaction 2a + b --&gt; c + d has an activation energy of 80.0 kj/mol. at 320°c, the rate constant k = 1.80 x 10-2 l mol-1 s-
Naddik [55]
To determine the k for the second condition, we use the Arrhenius equation which relates the rates of reaction at different temperatures. We do as follows:

ln k1/k2 = E / R (1/T2 - 1/T1) where E is the activation energy and R universal gas constant.

ln 1.80x10^-2 / k2 = 80000 / 8.314 ( 1/723.15 - 1/593.15)

k2 = 0.3325 L / mol-s
5 0
4 years ago
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