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pychu [463]
1 year ago
13

A voltaic cell is based on the following two half-reactions: ni 2(aq) 2e− → ni(s) e° = −0. 25 v cr 3(aq) 3e– → cr(s) e° = –0. 74

v sketch the cell and then select the correct statement about it
Chemistry
1 answer:
emmasim [6.3K]1 year ago
3 0

The net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

<h3>What is a half-cell reaction?</h3>

A half cell reaction is given as the oxidation or the reduction reaction that takes place at each of the anode or the cathode, forming the net redox reaction.

The cell potential and the half-reactions are:

Ni²⁺ + 2e⁻ = Ni (s)     E° = -0.25 V

Cr³⁺ + 3e⁻ = Cr (s)     E° = -0.74 V

The anodic reaction is given as:

Cr (s) = Cr³⁺ + 3e⁻     E° = 0.74 V

The cathodic reaction is given as:

Ni²⁺ + 2e⁻ = Ni (s)     E° = -0.25 V

Thus, the net reaction of the cell will be:

3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s)

The cell potential can be calculated as:

E° = E (cathode) + E (anode)

E° = 0.74 + (-0.25) V

E° = 0.49 V

Thus, the net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

Learn more about cell potential, here:

brainly.com/question/1313684

#SPJ4

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If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
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Answer:

Sr(OH)₂ will be the limiting reagent.

Explanation:

First of all, you should know the following balanced chemical equation:

2 H₂CO₃ + 2 Sr(OH)₂ → 4 H₂O + Sr₂(CO₃)₂

The balanced equation is based on the Law of Conservation of Mass, which says that matter cannot be created or destroyed. Therefore, the number of each type of atom on each side of a chemical equation must be the same.      

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). By stoichiometry the following amounts in moles react:

  • strontium hydroxide: 2 moles
  • carbonic acid: 2 moles

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Sr(OH)₂= 87.62 g/mole + 2*(16 g/mole + 1 g/mole)= 121.62 g/mole

You apply the following rule of three, if 121.62 grams of hydroxide are present in 1 mole, 12.5 grams in how many moles are they?

moles of strontium hydroxide=\frac{12.5 grams*1 mole}{121.62 grams}

moles of hydroxide= 0.103 moles

On the other hand, you have 150 ml of 3.5 M carbonic acid. Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you can apply the following rule of three: if in 1 L there are 3.5 moles of carbonic acid, in 0.150 L (being 1 L = 1000 mL, 0.150 L = 150 mL) how many moles of acid are there?

molesofcarbonicacid=\frac{0.150 L*3.5 moles}{1 L}

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Finally, to calculate the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 2 mole of strontium hydroxide reacts with , how much moles of carbonic acid will be needed if 0.103 moles of strontium hydroxide react?

molesofcarbonicacid=\frac{0.103 moles of strontium hydroxide*2 moles of carbonic acid}{2 moles of strontium hydroxide}

moles of carbonic acid= 0.103 moles

But 0.525 moles are available. Since more moles are available than you need to react with 0.103 moles of strontium hydroxide, <u><em>Sr(OH)₂ will be the limiting reagent.</em></u>

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