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3 years ago

Shawna, Dexter, and Tilana are solving the equation Negative 2.5 (5 minus n) + 2 = 15.

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

8 0

All students have the correct answer

mihalych1998 [28]3 years ago

3 0

Answer:

All students are correct

Step-by-step explanation:

Shawna, Dexter, And Tilana

You might be interested in

{80-78} + {243-98} =

kirza4 [7]

Answer:

147

Step-by-step explanation:

80-78=2

243-98=145

2+145=147

5 0

3 years ago

Calculate 12 x 15 by changing the numbers into friendlier numbers as we saw in the videos. Show how you work it out – write out

kondor19780726 [428]

Answer:

The product 12 × 15 in friendlier numbers is (10 + 2) × (10 + 5) = 180

Step-by-step explanation:

The parameter given are;

To 12 × 15 by changing the numbers into friendlier numbers

The product in 12 × 15 written with friendlier numbers (or in a simplified format can be given as follows;

12 × 15 = (10 + 2) × (10 + 5)

Which gives;

(10 + 2) × (10 + 5) = 10² + 10 × 5 + 2 × 10 + 2 × 5

From which we have;

10² + 10 × 5 + 2 × 10 + 2 × 5 = 100 + 50 + 20 + 10 = 180

Therefore;

12 × 15 = 180.

7 0

3 years ago

1. A MAP SCALE READS 1CM:5KM. IF A DISTANCE ON THE MAP MEASURES 7CM, THE ACTUAL DISTANCE WILL BE?. 2. A SCHOOL DINING HALL IS 35

Agata [3.3K]

Answer:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. $42^\circ$

5. 16.73 m

Step-by-step explanation:

Solution 1.

Reading of map scale = 1cm:5km

i.e. 1 cm is equivalent to 5 km

Measurement of map = 7 cm

Actual distance = Measurement of map $\times 5$

Actual distance = 7 $\times 5$ = 35 km

-------------------

Solution 2.

Length of dining hall = 35 m

Measurement of map = 7 cm

Scale = Measurement of map : Length of dining hall (i.e. ratio)

Scale = 7 cm :35 m = 1 cm : 5 m

-------------------

Solution 3.

Length of building = 30 m

Scale = 1 cm to 5m

5 m is equivalent to 1 cm on scale

1 m is equivalent to $\frac{1}{5}$ cm on scale

30m is equivalent to $\frac{1}{5} \times 30$ = 6 cm on scale

-------------------

Solution 4.

Angle of elevation of A from B = $42^\circ$

Angle of depression of B from A = ?

Please refer to the image attached, we can clearly observe that both the angles (i.e. angle of elevation from A to B and angle of depression from B to A )will be equal.

Angle of depression of B from A = $42^\circ$

-------------------

Solution 5.

Given that:

String length, or hypotenuse of triangle BC= 25 m

Angle of string with horizontal, $\angle B = 42^\circ$

Please refer to the attached image for the clear understanding of the situation.

To find:

Height, AC = ?

We can use trigonometric identity:

$sin\theta = \dfrac{Perpendicular}{Hypotenuse}$

$sinB = \dfrac{AC}{BC}\\\Rightarrow sin42^\circ = \dfrac{AC}{25}\\\Rightarrow AC = 25 \times 0.67\\\Rightarrow AC = 16.73 m$

============

So, the answers are:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. $42^\circ$

5. 16.73 m

7 0

3 years ago

Find the root(s) of the equation A) x= -4 B) x= -1,4 C) x=4 D) x= -4,4 Part B^

fiasKO [112]

What is the equation?

8 0

4 years ago

Subtracting unlike fractions 8/9 - 5/6

inn [45]

Hello,

Here is your answer:

The proper answer to your question is "1/18".

Here is how:

8*6=48
9*6=54
-
5*9=45
6*9=54

48-45=3

Which is 3/54!

3/3=1
54/3=18

Which means your answer is 1/18!

If you need anymore help feel free to ask me!

Hope this helps!

7 0

3 years ago