Answer:
30√3 ≈ 51.96 miles
Step-by-step explanation:
The distance between the two ships can be found using the Law of Cosines, or using your knowledge of the side relationships in special triangles.
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Each ship is traveling at 10 mph, so after 3 hours will have traveled 30 miles.
The triangle OS1S2 formed by the harbor and the two ship locations is an isosceles triangle with base angles of 30°. Each half of OS1S2 is a 30-60-90 triangle whose longer leg is √3 times half the hypotenuse. The sum of those two "longer legs" is the distance between the ships.
The distance between ships is 2×15√3 = 30√3 ≈ 51.96 miles.
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<em>Additional comment</em>
If you prefer to use the Law of Cosines, you are looking for the length of the side opposite the 120° angle in a triangle with sides of 30 miles.
c² = 30² +30² -2·30·30·cos(120°) = 30²(2-2·(-0.5)) = 3·30²
c = 30√3 . . . . . take the square root (miles)
Answer:
49开
Step-by-step explanation:
<em><u>Answers</u></em><em><u>: </u></em>
<em>4</em><em>.</em><em> </em><em>=</em><em>9.999</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em><u>Examplantion</u></em><em><u> </u></em><em><u> </u></em><em><u>:</u></em>
<em><u>5</u></em><em><u>×</u></em><em><u>2</u></em><em><u>÷</u></em><em><u>3</u></em><em><u>=</u></em><em><u>9.99999</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
a function of the coefficients of a polynomial equation whose value gives information about the roots of the polynomial.
Answer:
x = 3
Step-by-step explanation:
8 - 2x = 2
- 2x = 2 - 8
- 2x = - 6
- x = - 6/2
- x = - 3
x = 3