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Oksanka [162]
3 years ago
12

6x+4 Solve for x…………

Mathematics
2 answers:
kakasveta [241]3 years ago
6 0

Answer:

...................

s344n2d4d5 [400]3 years ago
4 0

Answer:

what are the options?

Step-by-step explanation:

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Find the midpoint of the segment formed by the points D(8, 6) and E(4, 10).
bixtya [17]
D (8, 6)
E (4, 10)

x_{midpoint} =  \cfrac{x_D+x_E}{2} = \cfrac{8+4}{2}=6 \\  \\  y_{midpoint} =  \cfrac{y_D+y_E}{2} = \cfrac{6+10}{2}=8


Answer: B. (6, 8)
6 0
3 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two
wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean =\lambda=2 errors  per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that a randomly selected page does not need to be retyped is given by :-

P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767

Hence, the required probability :- 0.6767

6 0
3 years ago
Sum of terms pre calc
Dominik [7]

Answer:

Sn

<em>Your</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>Option</em><em> </em><em>A</em><em> </em><em>.</em>

8 0
2 years ago
Answer the question with explanation;​
PSYCHO15rus [73]

Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0

Therefore, by the series divergence test, the series \sum_{n=1}^\infty\frac{n^2}{(n+1)^2} diverges.

EDIT: To VectorFundament120, if (x_n)_{n\in\mathbb N} is a sequence, both \lim x_n and \lim_{n\to\infty}x_n are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.

7 0
2 years ago
Read 2 more answers
Is the relation a function?
mario62 [17]

Yes it is because none of the x are the same number making it a function.

6 0
3 years ago
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