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3 years ago

Help please! I have 35 minutes left

Mathematics

1 answer:

barxatty [35]3 years ago

3 0

Answer:

1. Arc BC = 78°

2. Arc ABC = 180°

3. Arc ADB = 258°

4. Arc EC = 102°

Step-by-step explanation:

Question 1 explanation: Since ∠AFE and ∠CFB are vertical angles, that means their angle measure is equal, so Arc BC has an angle measure of 78°.

Question 2 explanation: Because AC is the diameter of circle F, this means that the angle measure of Arc ABC is 180°.

Question 3 explanation: Since the angle measure of AC is 180° and ∠AFE and ∠EFD are 78° and 54° respectively, that means Arc DFC has an angle measure of 48°. Because you already know ∠CFB is 78°, that means Arc ADB has an angle measure of 258°.

Question 4 explanation: You already know Arc DFC is 48°, so Arc EC has an angle measure of 102°.

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How many different triangles, if any, can be drawn with one 90° angle and side length of 5 cm and 12 cm?

FromTheMoon [43]

Only one triangle is able to be drawn with those measurements and angle

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4 years ago

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Alyssa is painting her bedroom blue. Each of four walls has dimensions 12.9 ft by 9.9 ft. How much area will she paint?

elixir [45]

Answer:

510.84 ft²

Step-by-step explanation:

Given that,

dimensions of wall = 12.9ft by 9.9ft

height of wall = 12.9ft

width of wall = 9.9ft

there are total 4 walls in a bedroom to be painted blue.

Formula to calculate area of one wall

<h3>Height x Width</h3>

Formula to calculate area of four walls

<h3>4 (Height x Width)</h3>

= 4( 12.9ft x 9.9ft)

= 4 (127.71 ft²)

= 510.84 ft²

So area Alyssa will paint = 510.84 ft²

<em>(assuming she will paint only wall s of her room not the ceiling)</em>

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4 0

4 years ago

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ss7ja [257]

The answer correct answer is a

8 0

3 years ago

A plane traveled 240 miles. The trip was with the wind. It took 3 hours. The trip back was into the wind. The trip back took 6 h

sveta [45]

Answer:

Plane speed is 60 miles/hour

Wind speed is 20 miles/hour

Step-by-step explanation:

Lets suppose the speed of the plane in still air is s and speed of the wind is w and since speed in the formula below equals speed of the plane plus the wind's speed so speed=s+w for this journey with the wind

$Speed=\frac{Distance}{Time}$

$Distance=Speed*Time$

For the first journey the trip with the wind:

$Distance=Speed*Time\\240=(s+w)(3)\\240/3=s+w\\s+w=80$

Here we got our first equation for the second equation we use the information from the second trip which was into the wind. Which means the speed here would be speed=s-w

$Distance=Speed*Time\\240=(s-w)*6\\240/6=s-w\\s-w=40$