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3 years ago

13

Select 1 answer choices: sizes averages distances areas perimeters

1 answer:

hammer [34]3 years ago

7 0

Answer:

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Step-by-step explanation:

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I don’t know how to do this question pls help

sineoko [7]

Answer:

Step-by-step explanation:

Triangle P is mapped onto Q so P is the initial triangle that will transformed.

We can rotate counterclockwise 90° but we cannot do it about the origin (0,0) because the red point (5, 1) will end up at ( -1, 5) .

We see that the point (5, 1) ends up at ( -2, 4) so the center of rotation is lower than the origin.

The transformation is rotation of 90° about the point (0,-1)

5 0

2 years ago

If measure angle acd=70 then measure angle bcd=

FinnZ [79.3K]

Answer: 35

Step-by-step explanation:

Angle ACD = 70

Angle BCD = 70/2 = 35

8 0

2 years ago

What is the volume of a cylinder with the base radius of 10 units and a height of nine units?

Otrada [13]

Answer:

$V = 2827.43\ units^3$ or $V = 900\pi\ units^3$

Step-by-step explanation:

The volume of a cylinder is calculated by the following formula

$V = \pi r^2 *h$

Where r is the radius of the cylinder and h is the height

In this case we know that the radius r of the base is:

$r=10\ units$

and

$h=9\ units$

So the Volume is:

$V = \pi (10)^2 *9$

$V = 900\pi\ units^3$

$V = 2827.43\ units^3$

7 0

3 years ago

Read 2 more answers

Which of the sets of equations represent the two lines graphed?

Oksi-84 [34.3K]

Answer:

B) y = x + 2 and y = -x - 4

Step-by-step explanation:

Let the equation of a straight line with x-intercept 'a' and y-intercept 'b' be

$\frac{x}{a} + \frac{y}{b} = 1$

The line with positive slope has x-intercept a=-2 and y-intercept b=2.

Its equation is:

$\frac{x}{ - 2} + \frac{y}{2} = 1$

Multiply through by 2

$- x + y = 2$

Solve for y,

$\boxed {y = x + 2}$

For the line with a negative slope,

the x-intercept is a=-4 and the y-intercept is b=-4

Its equation is

$\frac{x}{ - 4} + \frac{y}{ - 4} = 1$

Multiply through by -4

$x + y = - 4$

Solve for y

$\boxed {y = - x - 4}$

4 0

2 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

2 years ago