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AlexFokin [52]
3 years ago
13

Select 1 answer choices: sizes averages distances areas perimeters

Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

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Step-by-step explanation:

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I don’t know how to do this question pls help
sineoko [7]

Answer:

Step-by-step explanation:

Triangle P is mapped onto Q so P is the initial triangle that will transformed.

We can rotate counterclockwise 90° but we cannot do it about the origin (0,0) because the red point (5, 1) will end up at ( -1, 5) .

We see that the point (5, 1)  ends up at ( -2, 4) so the center of rotation is lower than the origin.

The transformation is rotation of 90° about the point (0,-1)

5 0
2 years ago
If measure angle acd=70 then measure angle bcd=
FinnZ [79.3K]

Answer: 35

Step-by-step explanation:

Angle ACD = 70

Angle BCD = 70/2 = 35

8 0
2 years ago
What is the volume of a cylinder with the base radius of 10 units and a height of nine units?
Otrada [13]

Answer:

V = 2827.43\ units^3  or V = 900\pi\ units^3

Step-by-step explanation:

The volume of a cylinder is calculated by the following formula

V = \pi r^2 *h

Where r is the radius of the cylinder and h is the height

In this case we know that the radius r of the base is:

r=10\ units

and

h=9\ units

So the Volume is:

V = \pi (10)^2 *9

V = 900\pi\ units^3

V = 2827.43\ units^3

7 0
3 years ago
Read 2 more answers
Which of the sets of equations represent the two lines graphed?
Oksi-84 [34.3K]

Answer:

B) y = x + 2 and y = -x - 4

Step-by-step explanation:

Let the equation of a straight line with x-intercept 'a' and y-intercept 'b' be

\frac{x}{a}  +  \frac{y}{b}  = 1

The line with positive slope has x-intercept a=-2 and y-intercept b=2.

Its equation is:

\frac{x}{ - 2}  +  \frac{y}{2}  = 1

Multiply through by 2

- x + y = 2

Solve for y,

\boxed {y = x + 2}

For the line with a negative slope,

the x-intercept is a=-4 and the y-intercept is b=-4

Its equation is

\frac{x}{ - 4}  +  \frac{y}{ - 4}  = 1

Multiply through by -4

x + y =  - 4

Solve for y

\boxed {y =  - x - 4}

4 0
2 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
2 years ago
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