Please help me solve 1/3x>-4
1 answer:
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The derivatives for the given functions are as follows:
a) -3.
b) -1.
c) 1.
d) 0.
<h3>What is the product rule for a derivative?</h3>The product rule for a derivative is given as follows:
[f(x)g(x)]' = f'(x)g(x) + g'(x)f(x).
Hence, at x = 6, we have that:
[f(x)g(x)]'(6) = f'(6)g(6) + g'(6)f(6).
Replacing the values given in this problem, we have that the answer for item a is:
[f(x)g(x)]'(6) = f'(6)g(6) + g'(6)f(6) = 2(-1) - 1(1) = -2 - 1 = -3.
<h3>What is the quotient rule for a derivative?</h3>The quotient rule for a derivative is given as follows:
Hence, at x = 6, we have that:
Then the derivative in item b is:
[2(-1) - (-1)(1)]/[(-1)^2] = -1/1 = -1.
<h3>What is the derivative for the square root of a function?</h3>Applying the chain rule, the derivative is given by:
Replacing at x = 6, the derivative for item c is given by:
1/2 x 2 = 1.
<h3>What is the derivative of a constant?</h3>The derivative of a constant is of 0. In item d, the multiplication of f(6) by g'(6) results in a constant, hence the derivative is of 0.
More can be learned about derivative rules at brainly.com/question/25081524
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