Notice that we need to look for the intervals of x and also for the intervals of y.<span> We can observe that t</span>here is a minimum between x = 0 and x = 1 because the graph is descending and then ascending and also the graph has a maximum value between y = -3 and y = -1.
Answer:
A. 1÷(X+1) (x-2)
some steps are directly
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Since there is no figure attached, I will describe the derivation of the ideal gas law. The combined
gas law has no official founder; it is simply the incorporation of the three
laws that was discovered. The combined gas law is a gas law that combines
Gay-Lussac’s Law, Boyle’s Law and Charle’s Law.
Boyle’s law states that pressure is inversely proportional with volume
at constant temperature. Charle’s law states that volume is directly
proportional with temperature at constant pressure. And Gay-Lussac’s law shows
that pressure is directly proportional with temperature at constant volume. The
combination of these laws known now as combined gas law gives the ratio between
the product of pressure-volume and the temperature of the system is constant.
Which gives PV/T=k(constant). When comparing a substance under different
conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.
Answer:
<em>y = - 3x + 4 </em>
Step-by-step explanation:
m = 
y - 
= m( x - 
) Point-slope form
y = mx + b Point-intercept form
(1, 1)
(2, - 2)
m = (- 2 - 1 ) / (2 - 1) = - 3
y - 1 = - 3( x - 1 )
<em>y = - 3x + 4</em>
Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays (
) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)
