Question

Help!!!!!!!!!find the equation of the linear function q(16)=1 that is parralel to f(x)=1/3x+39

Answer 1

Answer:

$q(x)= \frac{1}{3} x -\frac{13}{3}$

Step-by-step explanation:

So you have (16, 1)

When two linear functions are parallel, they have the same slope.

So function q also has a slope of 1/3x. You have a set of points so you can plug them in a slope intercept equation to find b.

y= mx+b

m= slope

y= y-intercept

1= 1/3(16) +b

1 - (16/3) = b

b= -13/3

so then, $y= \frac{1}{3} x -\frac{13}{3}$