Xy= 120
x= 7+y
(7+y)(y) = 120
y^2 + 7y - 120 = 0
(y + 15) (y - 8) = 0
Since we are finding two positive numbers,
If y= 8 then x= 15
The two numbers are 8 and 15
Answer:
d:) 1024
Step-by-step explanation:
Evaluate (4 x^3)^2 where x = 2:
(4 x^3)^2 = (4×2^3)^2
Multiply each exponent in 4×2^3 by 2:
4^2 (2^3)^2
Multiply exponents. (2^3)^2 = 2^(3×2):
2^(3×2)×4^2
4^2 = 16:
2^(3×2)×16
3×2 = 6:
2^6×16
2^6 = (2^3)^2 = (2×2^2)^2:
(2×2^2)^2 16
2^2 = 4:
(2×4)^2 16
2×4 = 8:
8^2×16
8^2 = 64:
64×16
| | 6 | 4
× | | 1 | 6
| 3 | 8 | 4
| 6 | 4 | 0
1 | 0 | 2 | 4:
Answer: 1024
Answer:
16 : 23
Step-by-step explanation:
23 is a prime number, so it can't be reduced
Answer:
7.3*
Step-by-step explanation:
do the inverse:
22/3=7.3*
*=recurring
Answer:
............................
Step-by-step explanation: