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2 years ago

Help!!!!!!!!!find the equation of the linear function q(16)=1 that is parralel to f(x)=1/3x+39

Mathematics

1 answer:

kkurt [141]2 years ago

6 0

Answer:

$q(x)= \frac{1}{3} x -\frac{13}{3}$

Step-by-step explanation:

So you have (16, 1)

When two linear functions are parallel, they have the same slope.

So function q also has a slope of 1/3x. You have a set of points so you can plug them in a slope intercept equation to find b.

y= mx+b

m= slope

y= y-intercept

1= 1/3(16) +b

1 - (16/3) = b

b= -13/3

so then, $y= \frac{1}{3} x -\frac{13}{3}$

You might be interested in

If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.

Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

$f(8) = 0$

Required

Find all zeros of the f(x)

If $f(8) = 0$ then:

$x = 8$

And $x - 8$ is a factor

Divide f(x) by x - 8

$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

7 0

2 years ago

Help please ! Please

gizmo_the_mogwai [7]

Answer:

15, 8, 25 The teacher payed 0.40 per book.

Step-by-step explanation:

4/10 = 2/5 Simplify the 4/10 to find the unit rate.

15: 2/5 = 6/x Set up your proportion.

2x =30 Cross multiply

/2 /2 Divide both sides by 2 to isolate x

x =15

8: 2/5 = x/20 Set up proportion

40 =5x Cross multiply

/5 /5 Divide both sides by 5 to isolate x

8 =x

25: 2/5 = 10/x Set up proportion

2x =50 Cross multiply

/2 /2 Divide both sides by 2 to isolate x

x =25

Graph: y=mx+b To graph, you will need to use y=mx+b format

y= 2/5 x+2 2/5 is your unit rate. Your rate changes every 2 books bought. To graph, start at (0,2) and go up 2 and to the right 5, plot. Continue moving up 2 and to the right 5 to graph.

The teacher payed 0.40 per book because 2/5 simplifies to 0.40.

8 0

3 years ago

Find the equation of the line.

Grace [21]

Answer:

m: $-\frac{1}{3}$

Step-by-step explanation:

Pick two points (0,5) and (3,4)

use the formula to find slope: $\frac{y2-y1}{x2-x1}$

Insert values: $\frac{4-5}{3-0}$

m: $-\frac{1}{3}$

:-)

7 0

2 years ago

What can be useful when finding the value of a variable

jeyben [28]

Writing an equation would be most helpful, but depending on the situation drawing a diagram or reading a table could work better.

8 0

3 years ago

Use a net to find the surface Area of the square pyramid The height of the pyramid is 9 yes and the base sides are all 2.5 yrds

Cerrena [4.2K]

Answer:

$Area = 51.68yd^2$

Step-by-step explanation:

Given

$h = 9yd$ -- height

$a = 2.5yd$ --- base sides

Required

Determine the surface area

The net is not given. So, I will solve directly.

The surface area is calculated as:

$Area = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}$

So, we have:

$Area = 2.5^2 + 2*2.5\sqrt{\frac{2.5^2}{4} + 9^2}$

$Area = 6.25 + 5\sqrt{\frac{6.25}{4} + 81}$

$Area = 6.25 + 5\sqrt{1.5625 + 81}$

$Area = 6.25 + 5\sqrt{82.5625}$

$Area = 6.25 + 5* 9.086$

$Area = 51.68yd^2$

6 0

3 years ago