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rosijanka [135]
2 years ago
7

Robin, who is self-employed, contributes $4500/year into a Keogh account. How much will he have in the account after 30 years if

the account earns interest at the rate of 2.5%/year compounded yearly?
Mathematics
1 answer:
pashok25 [27]2 years ago
4 0

Answer:

The amount that would be in the account after 30 years is $368,353

Step-by-step explanation:

Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly

We proceed to use the formula below;

A = [P(1 + r)^t-1]/r

From the question;

P is the amount deposited yearly which is $4,500

r is the interest rate = 2.5% = 2.5/100 = 0.025

t is the number of years which is 30

Substituting these values into the equation, we have;

A = [4500(1 + 0.025)^30-1]/0.025

A = [4500(1.025)^29]/0.025

A = 368,353.3309607034

To the nearest whole dollars, this is;

$368,353

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Answer:

linear function:  y = -7x + 150

Step-by-step explanation:

Scott's situation represents a linear function because he is spending $7 each day on lunch.  His initial amount in his bank account is $150 and each day he spends the same rate on lunch, $7.  So, for any amount of days - represented by 'x' in the equation, you would multiply by -7 (since he is spending) and subtract this amount from his original amount of $150.  In this equation, 'y' is equal to his total after 'x' amount of days.  

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mojhsa [17]

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<u>Solution:</u>

Given, series of elements are 2, \frac{10}{3}, \frac{50}{9}

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

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Hence, the common ratio of the given series is \frac{10}{6}

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