Answer:
A. No real solution
B. 5 and -1.5
C. 5.5
Step-by-step explanation:
The quadratic formula is:
, with a being the x² term, b being the x term, and c being the constant.
Let's solve for a.
We can't take the square root of a negative number, so A has no real solution.
Let's do B now.
So B has two solutions of 5 and -1.5.
Now to C!
So c has one solution: 5.5
Hope this helped (and I'm sorry I'm late!)
Answer:
no solutions
Step-by-step explanation:
3x+ 7(x+1) = 2(6x+5) -2x
Distribute
3x+7x+7 = 12x+10-2x
Combine like terms
10x+7 = 10x+10
Subtract 10 from each side
10x+7-10x = 10x+10-10x
7 = 10
This is not a true statement so there are no solutions
Answer:
X=2
Step-by-step explanation:
|2x -12| = -4x
2x-12 = -4x
2x - (-4x) = 12
2x +4x =6x
6x=12
x=12/6
x=2
First multiply them together
![\left[\begin{array}{ccc}a-6&2&ab\\2&1&5b\\-3&1+3b&2\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da-6%262%26ab%5C%5C2%261%265b%5C%5C-3%261%2B3b%262%5Cend%7Barray%7D%5Cright%5D%20)
A symmetric matrix is where the transpose is equal to original matrix.
This means row n = column n
Looking at row1 = column1 ----> ab = -3
Looking at row2 =column2 ----> 5b = 1+3b
Solve those 2 equations for a,b
b = 1/2
a = -6
Answer:
f(9) =21
Step-by-step explanation:
I will assume you want to find f(9) when x=9
Let x=9
f(9) = 2(9) +3
= 18+3
=21
f(9) =21
