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xxMikexx [17]
3 years ago
11

What is the probability of flipping a coin 85 times and getting tails 50 times or fewer? Round your answer to the nearest tenth

of a percent. O A. 95.9% O B. 99.8% C. 33.2% O D. 0.4%​
Mathematics
1 answer:
gladu [14]3 years ago
8 0

Answer:

Step-by-step explanation:

95.9

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Which statement best explains why the graphed relation is not a function?
shusha [124]

Answer:

c

Step-by-step explanation:

Because you can't have multiple x-values. You can only have multiple y-values.

4 0
3 years ago
Select the correct answer.<br> What is the value of g(2)
Mariulka [41]

Answer:

1

answer is D

Step-by-step explanation:

we must calculate it from this equation :

x³ -9x²+27x-25 then

{2}^{3}  -( 9 \times 4 )+ (27 \times 2) - 25 =  1

4 0
3 years ago
Order these numbers from least to greatest.
Lorico [155]

Answer:

1. -√19   2. 4.56   3. √21   4. 23/5

Step-by-step explanation:

6 0
3 years ago
While shopping at a clearance sale, Samantha finds a $60.00 dress on sale for 25% off. Samantha also has a 50% off coupon. Which
liq [111]

It seems most likely that ...

... Samantha will save $37.50 because she must first find the 25% sale price before taking the extra 50% reduction

_____

In the real world, it seems probable that Samantha will be offered the choice of using the coupon <em>or</em> the sale discount. If she chooses tht 50% coupon, her savings will be $30. If she chooses the marked sale discount, her savings will be $15.

The scenario above assumes she gets 50% off the sale price of $45, so saves $15+22.50 = $37.50 off the original price.

6 0
3 years ago
Read 2 more answers
At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

6 0
3 years ago
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