If what.. we need to know what it is
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7

Answer:
Conservation of energy, principle of physics according to which the energy of interacting bodies or particles in a closed system remains constant. ... For example, when a pendulum swings upward, kinetic energy is converted to potential energy.
Step-by-step explanation:
P=r x 2 x pi
= 3 x 2 x 3.14
= 6 x 3.14 = 18.84
Answer:1
Step-by-step explanation:
-2-(-3)
-2+3=1