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2 years ago

Heyyy, please answer :]

Mathematics

1 answer:

Yuliya22 [10]2 years ago

6 0

The solution is “no real solution”
Because the slope is the same, so they are parallel.

Hope that help!! :-)

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Expand and Simplify<br> 10a-(3a+7)

yuradex [85]

The answer would be 7(a - 1)

3 0

2 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

gizmo_the_mogwai [7]

Answer:

The other endpoint of the segment is $(-18,-7)$ .

Step-by-step explanation:

The midpoint of the points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the following formula:

$(x_m,y_m)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )$

where $(x_m,y_m)$ = coordinates of the midpoint.

We know that the midpoint is (-15, 2) and an endpoint is (-12, 11). Substituting the information we have gives:

$(-15,2)=(\frac{x_1-12}{2}, \frac{y_1+11}{2} )$

To find $x_1$ we need to solve this equation:

$-15=\frac{x_1-12}{2} \\\\\frac{x_1-12}{2}=-15\\\\\frac{2\left(x_1-12\right)}{2}=2\left(-15\right)\\\\x_1-12=-30\\\\x_1-12+12=-30+12\\\\x_1=-18$

and to find $y_1$ we need to solve this equation:

$2= \frac{y_1+11}{2} \\\\\frac{y_1+11}{2}=2\\\\\frac{2\left(y_1+11\right)}{2}=2\cdot \:2\\\\y_1+11=4\\\\y_1=-7$

The other endpoint of the segment is $(x_1,y_1)=(-18,-7)$ .

5 0

3 years ago

Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.

Naily [24]

The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube.

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

$V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}$

8 0

3 years ago

The chess club members bought 6 tickets to a tournament for $15. How much would they have paid if all 9 members wanted to go?

olga nikolaevna [1]

Answer:$22.50

Step-by-step explanation:You need to divide the cost by th numbers of objects to get the answer.15 divided by 6 equals $2.50. Since each ticket costs $2.50,you multiply 2.50 times 9 which gets you $22.50.

8 0

3 years ago

What is 5 3/4 times 2/6? I am doing math homework and need help

Jobisdone [24]

53/4•2/6=1 11/12
Because you must turn 5 3/4 into an improper fraction. So 23/4•2/6. Next you are able to cross reduce because 2 goes into 2 and four so now you have 23/2•1/6 now just multiply across. 2•6=12 and 23•1=23 so now you have 23/12 which equals
1 11/12

6 0

3 years ago

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