Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2
Answer:
12.686cm
Step-by-step explanation:
By using pythagoras, we can find CB.
We know that 
Therefore, 
(it has to be positive since it is distance)
now we look at triangle BCD and use SOH CAH TOA.
Answer:
[x-h]^2 + [y-k]^2 =r^2
Step-by-step explanation:
Let x and y be an arbitrary point along the circle
The equation of the circle is given as:
[x-h]^2 + [y-k]^2 =r^2
<span>Let the price (before tax) be x.
The tax is 7% of x, so it is 0.07x.
The price plus the tax add up to $45.
x + 0.07x = 45</span>
Answer:
C
Step-by-step explanation:
A line with a slope of 1/3 using the y=mx+b line slope equation would be:
y=1/3x+b
We can now plug the x and y values into this equation with x being -6 and y being 2.
2=1/3 * -6 +b
2= -2 +b
b=4
Therefore the equation is
y=1/3x+4
C
<em>I hope this helps! :)</em>
