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Black_prince [1.1K]
3 years ago
10

What is the name of a loop that electricity flows through?

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

I believe its 1. Circuit

Explanation:

I could be wrong, but I'm pretty sure.

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C. Fewer. it is a summary
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A generator contains a coil that spin to produce an electric current how is energy transformed by using a generator
Oxana [17]
Mechanical energy is transformed to electromagnet energy
4 0
3 years ago
Read 2 more answers
What volume of ammonia in liters, at STP, can be produced from 2.0 kg of hydrogen gas, H2, and an excess of nitrogen gas, N2? N2
Sonbull [250]
Ok so rewrite the equation for yourself :).

N2 + 3H2 -> 2NH3 (Always check if it is balanced).

Ok so we have 2kg of hydrogen conver this to grams and then to moles.
2kg -> 2000g
2000g divide by R.M.M of H2
R.M.M
2H - 2 * 1 -> 2
2000/2 - 1000 moles.
Look at the ratio of H2 to 2NH3.
We see that we get 2NH3 for every H2 therefore the ratio is 1:2.
This means that we HAVE 2000 moles of 2NH3.
At stp. we know that 1 moles = 22.4 Litres
We have 2000 moles that means that we produce 44800 litres of NH3 at stp.
2000 * 22.4 - 44800
Hope this helps :).

4 0
3 years ago
A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

⇒ V1 = the initial volume = 2.00 L

⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

7 0
4 years ago
decomposition of hydrogen peroxide produce water and oxygen . calculate the volume of O2 formed from the decomposition of 150 mL
Ugo [173]

Explanation:

2H2O2 => 2H2O + O2

Moles of hydrogen peroxide = 0.150dm³ * (0.02mol/dm³) = 0.003mol .

Moles of oxygen = 0.0015mol.

Volume of oxygen = 0.0015mol * (22.4dm³/mol) = 0.0336dm³.

5 0
3 years ago
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