<u>Answer:</u> The number of moles of is 0.05 moles.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Molarity of solution = 0.10 mol/L
Volume of solution = 1 L
Putting values in above equation, we get:
The chemical reaction for the ionization of sodium sulfate follows the equation:
By Stoichiometry of the reaction:
2 moles of sodium ions are produced by 1 mole of sodium sulfate
So, 0.10 moles of sodium ions will be produced by = of sodium sulfate.
Hence, the number of moles of is 0.05 moles.
Answer: 0.1 decrease in 15 minutes
unit rate is 0.1 / 15 = 0.00667
Temperature is decreasing by 0.00667 degrees Celsius per minute
Explanation:
Hope this helps !
Answer:
Explanation:
2 KCIO,(s) 2 KCI) + 3 02(g)
For every 3 moles of O2 you need 2 moles of KClO3
2/x = 3/15 Cross Multiply
3*x = 2 * 15 Combine the right
3x = 30 Divide by 3
3x/3 = 30/3 Combine
x = 10
1) State the balanced chemical equation
Na3 PO4 + 3 AgNO3 → 3NaNO3 + Ag3 PO4
sodium phosphate silver nitrate sodium nitrate silver phosphate
2) State the molar ratios
1 mol Na3PO4 : 3 mol AgNO3 : 3 mol NaNO3 : 1 mol Ag3 PO4
3) As you see 3 moles of Silver Nitrate react with 1 mol of Na3 PO4, then you will need.
The you need to use the molar ratio 1:3 to calculate the number of moles of sodium phosphate
1 mol Ag NO3 * [ 1 mol Na3 PO4 / 3 mol Ag NO3] = 0.33 mol Na3 PO4
Answer: 0.33 mol sodium phosphate
Hey there!
Molar mass of O3 = 47.9982 g/mol
therefore:
1 mole O₃ --------------------- 47.9982 g
moles O₃ ---------------------- 24 g
moles O₃ = 24 x 1 / 47.9982
moles O₃ = 24 / 47.9982
moles O₃ = 0.500 moles
Hope this helps!