A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
1 answer:
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Answer:
a. Approximately .
b. Approximately .
Explanation:
The unit of concentration "" is equivalent to "
", which means "moles per liter."
However, the volume of both solutions were given in mililiters . Convert these volumes to liters:
.
.
In a solution of volume where the concentration of a solute is
, there would be
(moles of) formula units of this solute.
Calculate the number of moles of formula units in each of the two solutions:
Solution in a.:
.
Solution in b.:
.
What volume of that (same as
)
solution would contain that many
For the solution in a.:
.
Convert the unit of that volume to milliliters:
.
Similarly, for the solution in b.:
.
Convert the unit of that volume to milliliters:
.
Answer:
-1.05 V
Explanation:
A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.
Oxidation half equation;
Sn(s) ------> Sn^2+(aq) + 2e
Reduction half equation:
Mn^2+(aq) + 2e ----> Mn(s)
Cell voltage= E°cathode - E°anode
E°cathode= -1.19V
E°anode= -0.14 V
Cell voltage= -1.19 V - (-0.14V)
Cell voltage= -1.05 V
