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Mathematics

1 answer:

Bogdan [553]3 years ago

5 0

Answer:

Thanks for the point!

Step-by-step explanation:

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Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

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3 years ago

If the reciprocal of the number $X$ equals $\frac{2}{7}$, what is $5$ divided by $X$?

grigory [225]

U can find the reciprocal of a number by flipping the number.
example : the reciprocal of 1/5 is 5/1....the reciprocal of 2/3 = 3/2.

the reciprocal of x = 2/7.....that means x = 7/2

5 / (7/2) = when dividing fractions, flip what u r dividing by, then multiply
5 * 2/7 =
10/7 or 1 3/7 <==

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3 years ago

Please help!

likoan [24]

Answer: 123

Step-by-step explanation:

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3 years ago

Becky has one piece of paper. She cuts the paper in half and then has two pieces. She cuts these in half to get four pieces. The

garri49 [273]

C.) p(1) = 1; p(n) = p(n-1) + 1

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