Answer:
The answer is "Option B".
Step-by-step explanation:
The difference between most time and also the least spending time on Internet surfing is 3 hours. Since we do not have charts for tables etc., only 3 can be used we need. A range is defined as the difference between the largest and the smallest amounts. The range between both the largest as well as the smallest is unique. In this reply, it tells us that the gap between most time and the fewer hours invested surfing the web is 3 hours.
- In option A, it is wrong since the range has nothing to do with formulas. (Of course, the dividend with a divisor results in a quotient). Only subtraction and not division may be achieved.
- In option C, when all surf for exactly one hour, it could take the largest time of 3 hours and 3 hours, the last time. Add it into the equation and the range of the data present would've been 0.
- In option D, It is erroneous even as the range is not the mean, and the mean seems to be the average. We search for both the range, not the mean.
Slope formula: Change in y over change in x
Change in y: +4
Change in x: +5
Slope: 4/5
Hope this helps :)
Please give brainliest
Using proportions, it is found that each of the 6 people got $0.5.
<h3>Proportions:</h3>
- This question is solved by <em>proportions</em>, using a rule of three.
- $3.00 is shared between 6 people, which are Larry, Curly, Moe, Alvin, Simon and Theodore. How much did each people(1 person) get?
The <em>rule of three</em> is:
$3.00 - 6 people
$x - 1 person
Applying cross multiplication:



Each of the 6 people got $0.5.
To learn more about proportions, you can take a look at brainly.com/question/24372153
Answer:
20/81
Step-by-step explanation:
Without parentheses, it is hard to tell what you are dividing. We assume you want ...
(4/9)/(9/5)
Then ...

_____
As written (without parentheses), your expression is evaluated left to right, so evaluates to ...
4/(9·9·5) = 4/405
Answer:
<u><em>−125a^(11)</em></u>
Step-by-step explanation:
<u><em>(−5a^(2)3a^(5) Then you solve</em></u>
<u><em>=−125a^(11)</em></u>