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3 years ago

Can someone help me in 3 pls

Mathematics

2 answers:

3241004551 [841]3 years ago

8 0

Rectangle + 2 x Sm. Triangles + lg. Triangle

In-s [12.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find the smallest perimeter and the dimensions for a rectangle with an area of 36 in^2

Tpy6a [65]

This is a square with area 36 in^2

So dimensions are 6 * 6 ins and perimeter = 24 ins.

3 0

3 years ago

What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Nadya [2.5K]

x-intercepts are found by setting y=0
$y=2x^2-8x-10\rightarrow0=2x^2-8x-10$
factor out a 2 $0=2(x^2-4x-5)\rightarrow0=x^2-4x-5$
 $0=(x-5)(x+1)$ roots should be x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)

y-intercepts are found by setting x=0
$y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10$
$\rightarrow y=0-0-10=-10$
therefore, y-intercept is (0,-10)

4 0

3 years ago

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago

You just started working for a company, where should you first look to find a confidentiality policy concerning the information

olasank [31]

It would be D because ur an employee and u need a handbook to see what ur handelling

4 0

3 years ago

What is the slope of this line?

nataly862011 [7]

Answer: $-\frac{8}{5}$

Remember: RISE/RUN (y/x). Lines that are increasing have a positive slope, and lines that are decreasing have a negative slope.

You can find the slope in two ways:

1. Useful if the line is graphed: count the units between 2 points on the line.

Let's use the points (-1, 4) and (4, -4).

(-1, 4) is 8 units higher than (4, -4) and 5 units to the left of (4, -4).

Because the line is decreasing, the slope is negative.

Therefore, the slope is $-\frac{8}{5}$ .

2. Useful if the line is not graphed: find the difference between the y-coordinate values divided by the difference of the x-coordinate values.

Let's use the points (-1, 4) and (4, -4).
$\frac{-4 - 4}{4 - (-1)} = \frac{-8}{5}$

Therefore, the slope is $-\frac{8}{5}$ .

4 0

3 years ago

Read 2 more answers