(5x2−3x−2)−(−2x2−x+10) in standard form please?
1 answer:
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Answer:
1.
2.
3.
Step-by-step explanation:
Standard form of a line is .
If a line passing through two points then the equation of line is
where, m is slope, i.e.,.
1.
The line passes through the points (7,-3) and (4,-8). So, the equation of line is
Therefore, the required equation is .
2.
We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to .
Slope of the line :
Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).
Equation of line is
Therefore, the required equation is .
3.
We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to .
From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).
Equation of line is
Therefore, the required equation is .
ANSWER
D.
EXPLANATION
The given graph rises on the left and falls on the right.
This implies that the degree of the function is even.
Since the graph opens downward, the coefficient of the leading term must be negative.
The graph graph of the function also has 3 intercepts with one of them having an even multiplicity.
This means that the degree must be 4.
Therefore the last choice is correct.