Answer:
12.7g of Cu
Explanation:
First let us generate a balanced equation for the reaction. This is illustrated below:
Zn + CuSO4 —> ZnSO4 + Cu
Molar Mass of Cu = 63.5g/mol
Molar Mass of CuSO4 = 63.5 + 32 + (16x4) = 63.5 + 32 + 64 = 159.5g/mol
From the equation,
159.5g of CuSO4 produced 63.5g of Cu.
Therefore, 31.9g of CuSO4 will produce = (31.9 x 63.5) / 159.5 = 12.7g of Cu
We will use this formula for first order:
㏑[A] = - Kt +Ao
when we have t (given)= 30 min = 30 x 60 = 1800 s (we here convert time from min to second.
then we assume that the initial concentration Ao = 1
and the concentration of A (final concentration = 0.25
So by substitution:
㏑(0.25) = - K * 1800 + ㏑(1)
1.39 = K * 1800
∴ K = 0.00077 s^-1 or 7.7 x 10^-4
1 mole of any gas under STP has volume =22.4 L
4.76 mol*22.4 L/1 mol ≈ 107 L
