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pashok25 [27]
4 years ago
10

How many moles of sodium carbonate na2co3 are contained by 57.3 g of sodium carbonate

Chemistry
1 answer:
yan [13]4 years ago
6 0
There are 0.54 moles of sodium carbonate are contained by  57.3 grams of sodium carbonate.

we can calculate number of moles in a compound by dividing number of grams of compound by the molar mass of the compound.
molar mass of sodium carbonate = 105.987 g/mol
now, 57.3 / 105.987 = 0.54 moles
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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
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Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

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Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

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2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

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3 years ago
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Dmitry_Shevchenko [17]

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The second equation is balanced

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This is because the number of elements of each atom in the product side equal the number of elements of each atom on the reactant side.

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4 years ago
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Answer:

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<em />

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