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3 years ago

How many moles of sodium carbonate na2co3 are contained by 57.3 g of sodium carbonate

1 answer:

6 0

There are 0.54 moles of sodium carbonate are contained by 57.3 grams of sodium carbonate.

we can calculate number of moles in a compound by dividing number of grams of compound by the molar mass of the compound.
molar mass of sodium carbonate = 105.987 g/mol
now, 57.3 / 105.987 = 0.54 moles

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2 years ago

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BlackZzzverrR [31]

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2 years ago

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Kisachek [45]

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so for this u have to use this equation where

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2 years ago

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ycow [4]

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Explanation:

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The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

For the given chemical reaction:

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The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]$

The enthalpy of formation for the substances present in their elemental state is taken as 0.

Here, iron is present in its elemental state which is solid.

Hence, for the given equation, only iron has the value of $\Delta H_f$ equal to 0 kJ.

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Answer:

the answer 37

Explanation:

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