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3 years ago

What would the answer be

Physics

1 answer:

wariber [46]3 years ago

6 0

Answer:

Explanation:

The density has a formula of d = m / V.

The volumes are given as the same.

The density will be

d_lead = 113/ V

d_aluminum = 27/V

It does not matter for this question what the volume actually is. Just note that the value of the volume is the same for each ball.

A: incorrect. If the volumes are the same, the density is not the same because the masses are different.

B: incorrect. If the density of the two balls was less than water, the two balls would float. Never going to happen unless the balls are thin shells.

C: incorrect. The exact opposite is the answer.

D: Correct. This is the answer.

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If different groups of scientist have access to the same data, how can they draw different conclusions?

Mkey [24]

I suppose they can interpret the data differently.

I hope this helps!

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4 years ago

if length of the spring is doubled, what will happen to its time period? if mass of the spring is doubled and spring constant wi

melamori03 [73]

If the length of the spring is doubled, there will be no effect on its period.

If the mass of the spring is doubled and the spring constant is halved, then its period will be doubled.

The Simple Harmonic Motion is a type of periodic motion and one of its examples is the spring-mass system.

The period of a spring mass system is given by the following equation,

T= 2π√m/√k

Here, T= period of spring

m= Mass of the body attached to the spring

k= Spring constant

According to the above equation, the period of a spring depends on the mass of the body and the spring constant.

It is independent of the length of the spring.

Therefore, if the length of spring is doubled then there will be no effect on its period.

If the mass of spring is doubled and the spring constant is halved, then the equation becomes

T'= 2π√2m/√k/2

T'= √4 x 2π√m/√k

T'= 2 x T

Hence, if the mass of the spring is doubled and the spring constant is halved, its period will be doubled.

To know more about the "spring-mass system", refer to the following link:

brainly.com/question/13156044?referrer=searchResults

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2 years ago

Convert 79.5 mi/h to m/s. 1 mi = 1609 m. Answer in units of m/s.

navik [9.2K]

Having a given problem of 79.5 miles per hour to be converted to meters per second, we need to know the constant values of 1 mile = 1609 meter, 1 hour = 60 minutes and 1 minute = 60 seconda. To solve, (79.5 mi/1 h)x(1609 m/ 1 mi)x(1 hr/60min)x(1 min/60 sec). The final answer would be 35.53 m/s.

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3 years ago

An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the

poizon [28]

Answer:

The value is $A = 0.014 \ m$

Explanation:

From the question we are told that

The mass of the object is $m = 2.0 \ kg$

The unstressed length of the string is $l = 0.08 \ m$

The length of the spring when it is at equilibrium is $l_e = 5.9 \ cm = 0.059 \ m$

The initial speed (maximum speed)of the spring when given a downward blow $v = 0.30 \ m/s$

Generally the maximum speed of the spring is mathematically represented as

$u = A * w$

Here A is maximum height above the floor (i.e the maximum amplitude)

and $w$ is the angular frequency which is mathematically represented as

$w = \sqrt{\frac{k}{m} }$

$u = A * \sqrt{\frac{k}{m} }$

=> $A = u * \sqrt{\frac{m}{k} }$

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

$b = l -l_e$