3 years ago

A bicycle rider travels 50.0 km in 2.5 hours. What is his average speed?

Physics

1 answer:

ycow [4]3 years ago

4 0

50km / 2.5 = 20 km per hour

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Hi gir_ls join nkd-mbja-nuj

GREYUIT [131]

Answer:

never lol

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2 years ago

The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands

Ghella [55]

Answer:

Pressure on both feet will be $500N/m^2$

Explanation:

Weight of the person F = 500 N

Area of foot print $A=0.5m^2$

Area of both the foot $A=2\times 0.5=1m^2$

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure $P=\frac{F}{A}$

$P=\frac{500}{1}=500N/m^2$

So the pressure on both feet will be $500N/m^2$ when person stands on both feet.

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3 years ago

A car is accelerated from 40 m/s to 48 m/s in 6.5 seconds. What is the magnitude of the car’s

pantera1 [17]

Answer:

Explanation:

AVerage acceleration is the cjange in velocity with time

a = v-u/t

v is the final velocity = 48m/s

u is the initial velocity = 40m/s

t is the time = 6.5s

a = 48-40/6.5

a = 8/6.5

a = 1.23m/s²

Hence the magnitude of the car’s average acceleration during this period is 1.23m/s²

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2 years ago

Use Hooke's Law, which states that the distance a spring stretches (or compresses) from its natural, or equilibrium, length vari

Phantasy [73]

Answer:

706.68 N

Explanation:

By Hooke's law,

$F = ke$

$k=\dfrac{F}{e}$

Using the values in the question,

$k=\dfrac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}$

When e = 0.4 m,

$F = 1766.7\text{ N/m}\times0.4\text{ m}=706.68\text{ N}$

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2 years ago

24. Use Newton’s first law of motion to explain how wearing a seat belt in a moving car would help prevent injury (3 points)

barxatty [35]

Idk sorry not sorry

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3 years ago