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AveGali [126]
2 years ago
8

The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this funct

ion?. . (1 point). y = x. y = 4x. y = x2. y = x3 The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this function?. . (1 point). y = x. y = 4x. y = x2. y = x3 @Mathematics
Mathematics
2 answers:
san4es73 [151]2 years ago
7 0
We can see in the points given that the x-coordinate of each point, when raised to a power of three or multiplied to itself three times, the value is equal to the y-coordinate of the point. Hence the answer to this problem which is a function is y = x^3.
Aleonysh [2.5K]2 years ago
3 0
Hmm

2 times 4=8
3 times 8 is not 27



1 times 1=1
2 times 4=8
3 times 9=27

aka
1 times 1^2=1
2 times 2^2=8
3 times 3^2=27
x times x^2=x^3

the rule is y=x^3

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Find the measurement of angle JGH
yaroslaw [1]

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
-3x^2-5x+9=0 what is the value for a,b,and c
Tju [1.3M]

Answer:

a = -3  b = -5  c = 9

Step-by-step explanation:

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ax^2 +bx +c =0

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3 0
2 years ago
Will upvote<br><br> 4,7,12,19,31,... does this classify as a arithmetic, geometric, or neither
spayn [35]
To find if a series is either geometric or arithmetic:
it must satisfy this property:

Arithmetic:

a(n+1) - a(n) = const

Geometric:

a(n+1)/a(n) = const

In your case:

r1 = 7 -4 = 3

r2 = 12 - 7 = 5

r1 != r2  (not arirthmetic)

Geometric check:

r1 = 7/4

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r1 != r2  (not Geometric)

so neither. 


8 0
3 years ago
Two equations are given below:
Sindrei [870]
\left \{ {{a - 3b = 16} \atop {a = b - 2}} \right.  \\  \\  \left \{ {{a = 16 + 3b} \atop { 16 + 3b = b - 2}} \right.  \\  \\  \left \{ {{a = 16 + 3b} \atop {3b - b = - 2 - 16}} \right.  \\  \\  \left \{ {{a =16 + 3b} \atop {2b  = -18}} \right.  \\  \\  \left \{ {{a=16 + 3b} \atop {b=-9}} \right.  \\  \\  \left \{ {{a=16 + 3b = 16 + 3*(-9) = 16 - 27 = -11} \atop {b=-9}} \right.

Answer a = -11, b = -9
8 0
2 years ago
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