Cos30 = sin(90 - 60) = √3/2, because cos and sin are complements
cos120 = cos(180 - 60) = -cos60 = -1/2
You have to divide and 512/14=36 and 8/14 and that simplified is 36 and 4/7.
Answer:
475.
Step-by-step explanation:
We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.
We will use z-score formula and normal distribution table to solve our given problem.

Top 60% means greater than 40%.
Let us find z-score corresponding to normal score to 40% or 0.40.
Using normal distribution table, we got a z-score of
.
Upon substituting our given values in z-score formula, we will get:





Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.
Answer:
Point A is in the interior of both circles
Step-by-step explanation:
<u><em>Verify each point</em></u>
we know that
Point H is in the interior of greater circle but is outside smaller circle
Point A is the center both circles, then is in the interior of greater circle and is in the interior of smaller circle
Point B is on the smaller circle and is in the interior of greater circle
therefore
Point A is in the interior of both circles