Answer is: 31,45%.
mrs₁(C₉H₁₆O₄-<span>azelaic acid) = 12g.
mr</span>₂(C₉H₁₆O₄) = 50g.
ω₂(C₉H₁₆O₄) = 15% = 0,15.
mrs₂(C₉H₁₆O₄) = mr₂·ω₂ = 50g·0,15 = 7,5g.
mrs₃(C₉H₁₆O₄) = mrs₁ + mr₂ = 12g + 7,5g = 19,5g.
mr₃ = mr₂ + mr₂ = 50g + 12g = 62g.
ω₃ = mrs₃÷mr₃ = 19,5g ÷ 62g = 31,45% = 0,3145.
Answer:
<h3>The answer is 3754.33 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 21.7 kg = 21700 g
volume = 5.78 cm³
We have
We have the final answer as
<h3>3754.33 g/cm³</h3>
Hope this helps you
<h3>
Answer:</h3>
22.06 Hours
<h3>
Explanation:</h3>
- Half life is the time it takes for a radioactive material or isotope to decay by half of its initial amount.
We are given;
Radioactive isotope Iodine-133
Initial counts per minute = 3150 counts
Counts after decay = 3055 per minute
Time taken = 1 hour
But, we know that to calculate the remaining amount of the radioactive isotope, then,
Remaining amount = Initial amount × 0.5^n , where n is the number of half-lives.
Therefore;
3055 counts = 3150 × 0.5^n
0.5^n = 0.9698
To get n
n = log 1 ÷ log 0.9698
= 0.044
But, n is given by dividing time and the number of half lifes
Therefore, half life = time ÷ Number of half lives
= 1 hour ÷ 0.044
= 22.60 hours
Therefore, the half life of iodine-133 is 22.60 hours