Question

According to VSEPR theory, the molecule PF6- has how many regions of electron density around the central atom (how many electron groups?) (enter a number from 1 to 6) PF6- will have (linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar) electronic geometry, and (linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar) molecular geometry.

Answer 1

Answer : The electronic geometry and the molecular geometry of the molecule will be octahedral.

Explanation :

Formula used  :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, $PF_6^-$

$\text{Number of electrons}=\frac{1}{2}\times [5+6+1]=6$

The number of electron pair are 6 that means the hybridization will be $sp^3d^2$ and the electronic geometry and the molecular geometry of the molecule will be octahedral.