Between phosphorous, sulfur, chlorine and argon, argon is the element that's the least likely to form an ionic bond with sodium.
Answer:
The transfer was essential to understand the mutation and the possibility of new, more resistant strains in microorganisms.
Explanation:
the transfer of microorganisms is based on the transfer of genetic data through conductive pathways that penetrate the membranes, called pili or genetic bridges.
These mutated genes with higher resistance are transmitted and resistance is generated in entire populations and even species.
Answer:
Sln
n=m/mr
n=25/100
n=0.25mole of Caco3
Malality =number of moles/volume (divided by number of moles both sides)
volume =Malality /number of moles
v=0.125/0.25
v=0.500L
I hope this help
Answer:
Magnesium
Explanation:
Using the KLMN styled electronic configuration, the electronic configuration of sulphur with atomic number 16 is 2, 8,6
What this means is that it needs extra 2 electrons to fill into its M shell to attain the octet configuration.
Now let’s look at Magnesium, with atomic number 12, the electronic configuration it has is 2,8,2.
This means it has 2 extra electrons to give away so as to attain its own stability.
The sulphur atom will gladly accept the two electrons which the magnesium atom wants to give away. This makes it the perfect element to be reacted with sulphur to make it attain its octet configuration
Answer:
the stronger light 5.5 m apart from the total illumination
Explanation:
From the problem's statement , the following equation can be deducted:
I= k/r²
where I = intensity of illumination , r= distance between the point and the light source , k = constant of proportionality
denoting 1 as the stronger light and 2 as the weaker light
I₁= k/r₁²
I₂= k/r₂²
dividing both equations
I₂/I₁ = r₁²/r₂²=(r₁/r₂)²
solving for r₁
r₁ = r₂ * √(I₂/I₁)
since we are on the line between the two light sources , the distance from the light source to the weaker light is he distance from the light source to the stronger light + distance between the lights . Thus
r₂ = r₁ + d
then
r₁ = (r₁ + d)* √(I₂/I₁)
r₁ = r₁*√(I₂/I₁) + d*√(I₂/I₁)
r₁*(1-√(I₂/I₁)) = d*√(I₂/I₁)
r₁ = d*√(I₂/I₁)/(1-√(I₂/I₁)) =
r₁ = d/[√(I₁/I₂)-1)]
since the stronger light is 9 times more intense than the weaker
I₁= 9*I₂ → I₁/I₂ = 9 →√(I₁/I₂)= 3
then since d=11 m
r₁ = d/[√(I₁/I₂)-1)] = 11 m / (3-1) = 5.5 m
r₁ = 5.5 m
therefore the stronger light 5.5 m apart from the total illumination
