If we plot the data on the graph, we can see that the
data is skewed to the right (positive skew) and there is an outlier. In skewed
data and presence of outlier, the median is most commonly used measure of
central tendency. This is because a positive skew would result in a positive
bias to the mean. Meaning that it would be a lot larger than the median and not
really representing the actual central tendency. The median however is less
affected by the skew and outliers.
Answer: Median, because the data are skewed and there is
an outlier
<span> </span>
Answer:
The first one
Step-by-step explanation:
The correct answer is option A. Erica is correct in saying that the two lines are not necessarily the same and we should also look at the y-intercepts before determining how many solutions there were. <span>Two lines with equal slopes could be the same line, but only if they have the same y-intercept.</span>
Start with the equation of a circle whose center is at (h,k) and whose radius is r:
(x-h)^2 + (y-k)^2 = r^2
Substituting the given coordinates of the center:
(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2
Substituding the given coordinates of a point (6,-2) on the circle:
(6-5)^2 + (-2+5)^2 = r^2
Simplifying:
1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2. Then r = sqrt(10).
