Answer:
200 grams
Step-by-step explanation:
Let us represent
The number of grams of
30% smarties = x
20% smarties = y
Hence:
x + y = 500
x = 500 - y
Hence:
30% × x + 20% × y = 24% × 500
0.3x + 0.2y = 120
Substitute 500 - y for x
Hence:
0.3(500 - y) + 0.2y = 120
150 - 0.3y + 0.2y = 120
Collect like terms
- 0.3y + 0.2y = 120 - 150
- 0.1y = -30
y = -30/0.1
y = 300
Solving for x
x = 500 - y
x = 500 - 300
x = 200
Hence,
The number of grams of
30% smarties = x = 200 grams
20% smarties = y = 300 grams
Therefore:
the mass of the 30% mix is required to make a 500 gram mixture that will have 24% Smarties by mass is 200 grams
2y = 2x + 12
y = -2x - 3
You have the value of y in the second equation
So you can substitute it in the first equation and find the value of x
2(-2x - 3) = 2x + 12
2(-2x) - 2(3) = 2x + 12
-4x - 6 = 2x = 12
You can add 6 to both sides and subtract 2x from both sides to find x
-4x - 6 + 6 = 2x + 12 + 6
-4x = 2x + 18
-4x - 2x = 2x - 2x + 18
-6x = 18
Divide both sides by -6
x = -3
Substitute x in equation (2) to find y
y = -2(-3) -3
y = 3
The solution is (-3, 3)
Answer:
f(x)5.79(3)^2 for task 1
Step-by-step explanation: