Answer:
Step-by-step explanation:
On a certain hot summer's day, 691 people used the public swimming pool. The daily prices are $1.50 for children and $2.25 for adults. The receipts for admission totaled $1260.75. How many children and how many adults swam at the public pool that day?
9514 1404 393
Answer:
(c) 5x and 3x, and 4 and 1
Step-by-step explanation:
Like terms have the same variable(s) to the same power(s).
The terms of this expression are ...
- x^3: variable x, power 3
- 5x: variable x, power 1
- -3x: variable x, power 1
- 3y: variable y, power 1
- 4: no variable
- -1: no variable
The like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.
Answer:
h(-2) = -1
Step-by-step explanation:
h(x)=-2x-5
Let x= -2
h(-2)=-2*-2-5
= 4 -5
h(-2) = -1
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
