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madreJ [45]
3 years ago
15

Which of the following affects how strongly anions and cations are attra

Chemistry
2 answers:
kozerog [31]3 years ago
8 0

Answer:

C. Neutrons .

Explanation:

  • You already have a cation ad an anion (a + and a - charge) and distance I think is how strong that attraction is. It varies as 1/r^2.
sertanlavr [38]3 years ago
5 0

Answer: A: Distance between anions and cations

Explanation: This is the right answer for Ape

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According to the following electron structure, how many valence electrons do these fluorine atoms have? F= 1s12s22p5
ddd [48]
The highest sequence for this shell is the number 2, preceding both the s and p in the diagram. This means that the outermost shell is the second level shell. In this shell, there are 7 electrons, 2 in the 2s orbital and 5 in the 2p orbital.

As a side note (not sure if this is a typo), the electron structure for fluorine begins with a 1s2, not a 1s1.
6 0
3 years ago
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How to study for a test on Isotopic Notations
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Just study it by looking it up
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4 years ago
Calculate the mass of water if the densityis 1.02 g/mL and the volume is 62 ml. M = (D(V)
schepotkina [342]

Answer:

<h2>The answer is 63.24 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 62 mL

density = 1.02 g/mL

The mass of the water is

mass = 1.02 × 62

We have the final answer as

<h3>63.24 g</h3>

Hope this helps you

7 0
3 years ago
Which cells contain this <br> organelle: plant cells, animal cells, or both?<br> ​blank
ser-zykov [4K]

Answer:

Eukaryotic

Explanation:

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3 0
1 year ago
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3 ( is ) . The equation for the
anyanavicka [17]

Answer:

The answer to your question is  52.35 g of O₂

Explanation:

mass of oxygen = ?

mass of KClO₃ = 66.8 g

Chemical balanced reaction

              KClO₃   ⇒   2 KCl  +   3O₂

Process

1.- Calculate the molar mass of KClO₃ and Oxygen

KClO₃ = 39 + 35.5 + (16 x 3) = 122.5 g

O₂ = 16 x 6 = 96 g

2.- Write proportions to solve this problem

                     122.5 g of KClO₃ -----------------  96 g of O₂

                        66.8 g              -----------------  x

                        x = (66.8 x 96) / 122.5

                        x = 6412.8/122.5

                        x = 52.35 g of O₂

4 0
4 years ago
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