Answer is: Ka for propanoic acid is 6,57·10⁻⁵.
Chemical reaction: C₂H₅COOH(aq) + H₂O(l) ⇄ C₂H₅COO⁻(aq) + H₃O⁺(aq).
n(C₂H₅COOH) = 0,04 mol.
V(C₂H₅COOH) = 750 mL = 0,75 L.
c(C₂H₅COOH) = 0,04 mol ÷ 0,75 L.
c(C₂H₅COOH) = 0,053 mol/L = 0,053 M.
[C₂H₅COO⁻] = [H₃O⁺] = 1,84·10⁻³ M = 0,00184 M.<span>
[HCN] = 0,053 M - 0,00184 M = 0,0515 M.
Ka = [</span>C₂H₅COO⁻] ·
[H₃O⁺] / [C₂H₅COOH].
Ka = (0,00184 M)² / 0,0515 M.
Ka = 6,57·10⁻⁵.
Answer:
Cheese will be limiting reactant.
Explanation:
In given question it is stated that two slices of breads are required for one sandwich. The total bread slices available are 52. we divide the 52 by 2 to determine the number of sandwich which could made from 52 slices.
52/2 = 26
26 sandwich could be made from 52 bread slices.
The amount of cheese required for one sandwich is 3 slices. The available slices of cheese are 69.
69/3 = 23
we can see that only 23 set of slices of cheese are available while bread slices are available for 26 sandwiches. so we can make only 23 sandwiches from given quantity of ingredients. The 6 slices or 3 set of bread will left, because cheese is limited.
Answer:
wavelength = 1.71× 10⁻⁶ m
Explanation:
Given data:
Wavelength of wave = ?
Frequency of wave = 1.75×10¹⁴ s⁻¹
Solution:
Formula:
Speed of light = wavelength × frequency
wavelength = Speed of light / frequency
Now we will put the values in formula.
wavelength = 3 × 10⁸ m/s / 1.75×10¹⁴ s⁻¹
wavelength = 1.71× 10⁻⁶ m
Explanation:
ok that is ans k............
