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Margarita [4]
3 years ago
9

A gas is at 5 Kelvin and 1 m3. The temperature is raised to 10 Kelvin. What is the new volume?2 m32 m5 m

Chemistry
1 answer:
Alja [10]3 years ago
5 0

For this question, suppose the pressure is remained constant, we can use the Charles law to find the answer.


Charles law:

V1/T1 = V2/T2


V1 and T1 are the initial volume and temperature (in K), and V2 and T2 are the final volume and temperature.


We just need to substitute in the numbers in order to find the new volume, V2.

1/5 = V2/10

5V2 = 10

V2 = 2


Therefore, the answer would be 2m3.

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Does the hydrogen molecule obey the octet rule?
Alja [10]

Explanation:

Hydrogen does not obey the octet rule. Boron does not always

obey the octet rule and in fact forms Lewis acids such as BF3 which

only has 6 electrons.

6 0
3 years ago
P4O10(s) = -3110 kJ/mol H2O(l) = -286 kJ/mol H3PO4(s) = -1279 kJ/mol Calculate the change in enthalpy for the following process:
mash [69]

Answer:

-290KJ/mol

Explanation:

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}

ΔHrxn = 4(-1279) - [6(-286) - 3110]

= -5116 -(-1716-3110)

= -5116-(-4826)

= -5116 + 4826 = -290KJ/mol

6 0
2 years ago
How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?
Zielflug [23.3K]

Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Molarity x volume

Substitution

Number of moles = 1 x 0.75

Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

                          34.5 g of KCl ----------------  1 mol

                             x                  ----------------  0.75 moles

                            x = (0.75 x 34.5) / 1

                            x = 25.9 g of KCl

3 0
3 years ago
Will give 20 points and brainliest help
Blababa [14]

the answer you have chosen is correct

8 0
2 years ago
What experimental evidence can you provide that the product isolated is 1-bromobutane?
Blizzard [7]
The experimental evidence that you could provide that <span> the product isolated is 1-bromobutane would be the changes that happens that are observable by the naked eye. Hope this helps. Have a nice day. Feel free to ask more questions.</span>
5 0
3 years ago
Read 2 more answers
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