All categories

4 years ago

A gas is at 5 Kelvin and 1 m3. The temperature is raised to 10 Kelvin. What is the new volume?2 m32 m5 m

Chemistry

1 answer:

Alja [10]4 years ago

5 0

For this question, suppose the pressure is remained constant, we can use the Charles law to find the answer.

Charles law:

V1/T1 = V2/T2

V1 and T1 are the initial volume and temperature (in K), and V2 and T2 are the final volume and temperature.

We just need to substitute in the numbers in order to find the new volume, V2.

1/5 = V2/10

5V2 = 10

V2 = 2

Therefore, the answer would be 2m3.

You might be interested in

A hot air ballon will rise in air because:

solmaris [256]

Answer: C

Explanation:

Hot air is a lot less dense for a few reasons. Hot air essentially means the particles have more kinetic energy, and move around a lot more. Cold air is dense because the particles move a lot less, have less energy, and are closer together.

7 0

3 years ago

Read 2 more answers

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

Help please and thank you for who ever

Korolek [52]

Answer:the first one

Explanation:

7 0

2 years ago

Read 2 more answers

Which of the following is generally true of female bones in relationship to male bones?

gtnhenbr [62]

What are the options

6 0

3 years ago

What is the most abundant metalloid in the universe

yan [13]

The answer is Scicillion

3 0

3 years ago