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prohojiy [21]
3 years ago
5

____KClO3 ---> ____KCl+ _____O2 2, 2, 3 1, 3, 2 2, 3, 3 3, 2, 2

Chemistry
1 answer:
AVprozaik [17]3 years ago
3 0

Answer:

2KClO3--------->2KCl + 3O2

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Why is Copper(II) Oxide "CuO" instead of "Cu2O"
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A mieral is ______<br><br>a. man-made<br><br>b. alive<br><br>c. non-living<br><br>d. a plant​
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6 0
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A small ferret comes to help Roxie with the rock that is blocking her den. They push with a total force of 90 N moving the bould
galina1969 [7]

Answer:

Work = 450 J

Explanation:

Force = 90N

Distance = 5m

Work = ?

The relationship between these quantities is given by the equation:

Work = Force * Distance

Work = 90 * 5

Work = 450 J

3 0
3 years ago
Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.60ft.
Damm [24]

<u>Given:</u>

Dimensions of the room= 12 ft * 15 ft * 8.60 ft

<u>To determine:</u>

The amount of HCN that gives the lethal dose in the room with the given dimensions

<u>Explanation:</u>

As per the World Health Organization, the lethal dose of HCN is around 300 ppm

300 ppm = 300 mg of HCN/ kg of inhaled air

Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³

Now,  1 ft³ = 28316.8 cm³

Therefore, the calculated volume of air corresponds to:

1548 * 28316.8 = 4.383 * 10⁷ cm3

Density of air (at room temperature 25 C) = 0.00118 g/cm3

Thus mass of air corresponding to the calculated volume is

Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3

= 5.172*10⁴ g = 51.72 kg

Lethal amount of HCN corresponding to 51.72 kg of air would be.

= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg

Ans: Lethal dose of HCN = 15.5 g

5 0
3 years ago
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