Answer:
The missing value is(0,0)
Step-by-step explanation:
The complete question is:
2x+3y=5x-y
Complete the missing value in the solution to the equation.
( ,0)
<u>Solution:</u>
We have given:
2x + 3y = 5x - y
Combine the like terms:
2x-5x= -y-3y
-3x = -4y
Both negative signs will be cancelled out by each other.
So we have,
3x = 4y
We have given y = 0
Then
3x = 4*0
3x= 0
Divide both sides by 3
3x/3 = 0/3
x = 0
y=0
Therefore missing value is(0,0)
Area=πr^2
find the area then divide by 8
we know that diameter=2radius or diameter/2=radius so
12=diameter
12/2=radius=6
subsitute
area=π(6)^2
area=36π
divide 36π by 8
36π/8=18π/4=9π/2π=4.5π
area of one section is 4.5π square feet or if we aprox pito 3.14159 then we get
4.5(3.14159)=area=14.1372 square feet or 14.14 square feet
Answer: x=−3
Step-by-step explanation: Let's solve your equation step-by-step.
2
3
(3x+9)=−2(2x+6)
Step 1: Simplify both sides of the equation.
2
3
(3x+9)=−2(2x+6)
(
2
3
)(3x)+(
2
3
)(9)=(−2)(2x)+(−2)(6)(Distribute)
2x+6=−4x+−12
2x+6=−4x−12
Step 2: Add 4x to both sides.
2x+6+4x=−4x−12+4x
6x+6=−12
Step 3: Subtract 6 from both sides.
6x+6−6=−12−6
6x=−18
Step 4: Divide both sides by 6.
6x
6
=
−18
6
x=−3
Answer:
The first step would be to look at the first two numbers (which is 27) and estimate which <u>multiple</u> of 5 is closest and <u>below</u> 27.
5*5 = 25
So once she got 25, she will need to subtract 27-25, which will give her 2. REMEMBER: 5 is the first number of the quotient.
Now, she will need to drag the last digit left of 275 (which is 5) to the remainder 2 and think what multiple of 5 will give her the answer 25.
Again, 5*5 = 25
Once again, her numbers on the quotient will be 55. That's the answer.
let's firstly convert the mixed fractions to improper fractions.
![\bf \stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}}~\hfill \stackrel{mixed}{1\frac{1}{3}}\implies \cfrac{1\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{4}{3}} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B7%7D%7B2%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%203%2B1%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf \begin{array}{ccll} miles&hours\\ \cline{1-2}\\ \frac{7}{2}&1\\[0.8em] m&\frac{4}{3} \end{array}\implies \cfrac{~~\frac{7}{2}~~}{m}=\cfrac{~~1~~}{\frac{4}{3}}\implies \cfrac{7}{2m}=\cfrac{3}{4}\implies 28=6m \\\\\\ \cfrac{28}{6}=m\implies \cfrac{14}{3}=m\implies 4\frac{2}{3}=m](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20miles%26hours%5C%5C%20%5Ccline%7B1-2%7D%5C%5C%20%5Cfrac%7B7%7D%7B2%7D%261%5C%5C%5B0.8em%5D%20m%26%5Cfrac%7B4%7D%7B3%7D%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B~~%5Cfrac%7B7%7D%7B2%7D~~%7D%7Bm%7D%3D%5Ccfrac%7B~~1~~%7D%7B%5Cfrac%7B4%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B7%7D%7B2m%7D%3D%5Ccfrac%7B3%7D%7B4%7D%5Cimplies%2028%3D6m%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B28%7D%7B6%7D%3Dm%5Cimplies%20%5Ccfrac%7B14%7D%7B3%7D%3Dm%5Cimplies%204%5Cfrac%7B2%7D%7B3%7D%3Dm)
