3 years ago

The pressure of a compressed gas is 1.45 atm. What is this pressure in kPa

Chemistry

1 answer:

Arte-miy333 [17]3 years ago

5 0

Answer:

1.45 Atmospheres = 146.92125 Kilopascals, or about 146.9 Kilopascals

Explanation:

1 Atmosphere = 101.325 Kilopascals, so 101.325 Kilopascals x 1.45 Atmospheres = 146.92125 Kilopascals.

You might be interested in

The voltaic cell made up of cobalt, copper, and their m2+ ions, has e°cell = 0.62 v. if e° of the cathode half-cell is 0.34 v, w

Colt1911 [192]

Since that E°cell =E°cathode - E°anode then
0.62V = 0.34 - E°anode
Therefore E° anode is = -0.28V

4 0

4 years ago

Read 2 more answers

Which statement describes a reason scientists predict that carbon dioxide emissions will increase over the next few decades? Cho

Ad libitum [116K]

Answer:

Many countries are undergoing an increase in technology and standard of living.

Explanation:

7 0

3 years ago

What does an atomic number represent in an atom? 1. Number of protons 2. Number of electrons. 3. Number of neutrons. 4. Number o

WINSTONCH [101]

4: The mass amount of protons and neutrons in an atom

We just covered this in my chem class

5 0

4 years ago

Read 2 more answers

Please Help , Thank You

Mazyrski [523]

The 3rd option is the answer

7 0

3 years ago

Read 2 more answers

PLS HELPPP How many moles of oxygen atoms (not molecules) are present in 6.41×1025 molecules of dinitrogen pentoxide (N2O5)? 1.

olga55 [171]

Answer:

(4) 266 moles

Explanation:

We have Dinitrogen Pentoxide N2O5

6.41*10^25 molecules are given

No of Moles of N2O5 = $\frac{No of Molecules }{Avogadro's Number}$

= $\frac{6.41 * 10^25}{6.022*10^23}$

= 106.5 mol

Now using Unitary Method

2 Mole of Nitrogen pentoxide require 5 mole of Oxygen to form N2O5

1 mole of N = $\frac{5}{2}*O$

In 106.5 mole of N = $\frac{5}{2}*106.5$ = 266.25 mole

So, 6.41*10^25 molecules of N2O5 will require 266.25 mole of Oxygen atoms.

5 0

3 years ago