Difference between intermediate and activated complex

Chemistry

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

The activated complex is an unstable (unobserved) structure corresponding to an energy maximum in the reaction profile. An intermediate is the chemical structure present at the transition state. An activated complex can not be isolated or observed in a chemical reaction.

Explanation:

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HELP I WILL MARK YOU AS THE BRAINLIEST ANSWER

borishaifa [10]

Hey there! Here is the answer:

B.) decrease; increase

Here's why:

As you move from left to right across a period on the periodic table the size of an atom will decrease. As you move from top to bottom down a group on the periodic table the size of an atom will increase.

I really hope this answer helps you out! :)

8 0

3 years ago

the pressure and temperature of 10 liters of gas are doubled. if the original condition are 2 atmosphere of pressure and 400k wh

Harman [31]

Answer:

$\boxed{\text{10 L}}$

Explanation:

We have two pressures, two temperatures, and one volume.

This looks like a question in which we can use the Combined Gas Law to calculate the volume.

$\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}$

Data:

$\begin{array}{rclrclrcl}p_{1}& =& \text{2 atm}\qquad & V_{1} &= & \text{10 L}\qquad & T_{2}& =& \text{400 K}\\p_{2}& =& \text{4 atm}\qquad & V_{2} &= & \text{?}\qquad & T_{2}& =& \text{800 K}\\\end{array}$

Calculation:

$\begin{array}{rcl}\dfrac{2 \times 10}{400}& =& \dfrac{4V_{2} }{800}\\\\0.050& = &0.0050V_{2}\\V_{2}& = &\mathbf{10 L}\end{array}\\\text{The final volume is }\boxed{\textbf{10 L}}$