All categories

3 years ago

Difference between intermediate and activated complex

Chemistry

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

The activated complex is an unstable (unobserved) structure corresponding to an energy maximum in the reaction profile. An intermediate is the chemical structure present at the transition state. An activated complex can not be isolated or observed in a chemical reaction.

Explanation:

You might be interested in

Trisha and her lab partner were conducting a variety of experiments to produce gases: hydrogen, oxygen, and carbon dioxide. In o

GaryK [48]

<u>Given:</u>

Volume of HCl = 150 ml

Molarity of HCl = 0.10 M

<u>To determine:</u>

The # moles of HCl

<u>Explanation:</u>

The molarity of a solution is the number of moles of a solute dissolved in a given volume

In this case:

Molarity of HCl = moles of HCl/volume of the solution

moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles

Ans: A)

Moles of HCl is 0.015

7 0

3 years ago

Bf3 can be octet or not

makvit [3.9K]

Answer:

(BH3 follows the octet rule by dimerizing, as Hadi Kurniawan AR pointed out.) For H and He, an "octet" = 2 electrons. Boron does prefer to follow the octet rule, in that it likes to form borate compounds such as NaBH4. It also is happy to form compounds with elements with lone pairs.

7 0

3 years ago

Pick a "for every" statement about copper and silver nitrate for this reaction.

maxonik [38]

From the equation of the reaction; for every 1 mole of copper, the reaction uses 2 moles of silver nitrate.

<h3>What is a reaction?</h3>

A chemical reaction involves the transformation of one chemical specie into another. The reaction is not shown here hence the question is incomplete.

However, the reaction should be of the sort; Cu + 2AgNO3 ---> Cu(NO3)2 + Cu. Thus, for every 1 mole of copper, the reaction uses 2 moles of silver nitrate.

Learn more about chemical reaction: brainly.com/question/6876669

8 0

2 years ago

Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an

ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

Ti $Cl_{4(l)}$ ⇒ Ti $Cl_{4(g)}$

ΔH° $_{f}$ (Ti $Cl_{4(l)}$ ) = -804.2 kJ/mol

ΔH° $_{f}$ (Ti $Cl_{4(g)}$ ) = -763.2 kJ/mol

Therefore,

ΔH° $_{f}$ = ΔH° $_{f}$ (Ti $Cl_{4(g)}$ ) - ΔH° $_{f}$ (Ti $Cl_{4(l)}$ ) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(Ti $Cl_{4(l)}$ ) = 221.9 J/(mol*K)

s°(Ti $Cl_{4(g)}$ ) = 354.9 J/(mol*K)

Therefore,

s° = s° (Ti $Cl_{4(g)}$ ) - s°(Ti $Cl_{4(l)}$ ) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH° $_{f}$ /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

5 0

3 years ago

Show the mechanism for the following reaction conducted at –5 °C in CCl4: cyclohexene bromine yields a dibromocyclohexane Draw w

Darya [45]

Answer:

See attachment.

Explanation:

In the first step, a cyclic structure with a positive bromine is formed. The bromine shares the positive charge with the two carbons that it is bonded to, so the carbons are partially positive.

The second bromine atom then attacks the carbon center, coming in from below the first bromine atom ("backside attack") where the antibonding orbital of the second bromine atom is.

The stereochemistry of the mechanism causes the final product to be an anti-dibromocyclohexane.

7 0

3 years ago

Difference between intermediate and activated complex​

Difference between intermediate and activated complex