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Setler [38]
2 years ago
7

Do sample problem 13.8 in the 8th ed Silberberg book. You add 1.4 kg of ethylene glycol (C2H6O2) antifreeze to 4,192 g of water

in your car's radiator. What is the boiling point of the solution? The Kb for water is 0.512 °C/m. Enter to 2 decimal places.
Chemistry
1 answer:
zmey [24]2 years ago
7 0

Answer:

The solution boils at 102.76 °C

Explanation:

Δt = m* Kb x i  

i = 1 with 1 particle in solution

m = molality

Kb = 0.512 °C/molal

Step 2: Calculate moles C2H6O2

molar mass of  C2H6O2 = 62.068 g/mol

Calculate number of moles:

Moles = Mass / molar mass

Moles = 1400 grams / 62.068 g/mol

Moles C2H6O2 = 22.56 moles

Step 3: Calculate molality

these are in 4192 g of water:

22.56 moles / 4.192 kg water

⇒ moles / kg of water = 5.38 moles / Kg = m olal

Step 4: Calculate  ΔT

ΔT= Kb * molal = 5.38 molal* 0.512 °C/m

ΔT = 2.76 °C

Boiling point = 100°C + 2.75 °C = 102.76 °C

the solution boils at 102.76 °C

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nydimaria [60]

Balanced equation(That should be NaClO_3)

\\ \rm\Rrightarrow Cl_2+2NaOH\longrightarrow NaCl+NaClO_3+H_2O

Remember that it's a ionic equation not general equation

So

We have to balance it accordingly

5 0
1 year ago
Read 2 more answers
Darryl finds a bottle of what looks like clear water, with dirt settled at the bottom. When he shakes the bottle, the water gets
Mazyrski [523]

Answer: The correct answer is Heterogeneous mixture

Explanation:

Heterogeneous mixture are those mixture in which:

  • Substance is distributed in non uniform manner.
  • Two distinct layers are formed

Thus when water and dirt are mixed together it results in the formation of  a heterogeneous mixture and after sometimes two different layers will be observed.

Hence, in the bottle there is a heterogeneous mixture of water and dirt.


3 0
3 years ago
Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
3 years ago
For which one of the following molecules is the indicated type of hybridization not appropriate for
Aleksandr [31]

A. BeCl2 sp2

Also when you get the chance, could you mark me brainliest?

7 0
3 years ago
Label the parts of the respiratory system.
Evgesh-ka [11]

Answer:

1. Nose

2. Mouth

3. Larynx

4. Lung

5. RIght Bronchi

6. Diaphragm

7. Pharynx

8. Trachea

9. Left Bronchi

10. Bronchioles

11. Avoli

Explanation:

8 0
2 years ago
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